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Worked Examples · Example 5.8

Q.To simulate car accidents, auto manufacturers study the collisions of moving cars with mounted springs of different spring constants. Consider a typical simulation with a car of mass 1000 kg1000\ \text{kg} moving with a speed 18.0 km/h18.0\ \text{km/h} on a smooth road and colliding with a horizontally mounted spring of spring constant 5.25×103 N m−15.25 \times 10^{3}\ \text{N m}^{-1}. What is the maximum compression of the spring?

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On the smooth road all the car's kinetic energy is stored in the spring at maximum compression, giving x=vm/k≈2.18 mx = v\sqrt{m/k} \approx 2.18\ \text{m} for the spring constant stated in the question.

On a frictionless road no energy is dissipated, so at maximum compression the car is momentarily at rest and its entire initial kinetic energy has become the spring's elastic potential energy.

Convert the speed to SI units

v=18.0 km h−1=18.0×10003600=5.00 m s−1.v = 18.0\ \text{km h}^{-1} = 18.0 \times \frac{1000}{3600} = 5.00\ \text{m s}^{-1}.

Energy conservation at maximum compression

12mv2=12kx2⇒x=vmk.\tfrac{1}{2}mv^2 = \tfrac{1}{2}kx^2 \quad\Rightarrow\quad x = v\sqrt{\frac{m}{k}}. …

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