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Exercises · Q4

Q.For the following arithmetic expression:
((2+3)*(4/2))+2
Show step-by-step process for matching parentheses using stack data structure.

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This question asks you to trace how a stack validates matching parentheses in an arithmetic expression — a core application of the LIFO (Last In, First Out) principle.

Why a Stack for Parentheses Matching?

The stack is the perfect tool here because parentheses must close in the reverse order they opened. When you see an opening bracket (, you push it onto the stack. When you see a closing bracket ), you pop the most recent opening bracket from the stack and check they match. If at any point you try to pop from an empty stack, or if the stack isn't empty at the end, the parentheses are mismatched.

This is not about evaluating the expression — it's purely about checking whether every opening parenthesis has a correctly placed closing partner.

Step-by-Step Trace

We'll scan the expression ((2+3)*(4/2))+2 character by character, tracking the stack state. Only ( and ) affect the stack; numbers and operators are ignored for this check.

StepCharacterActionStack (top → bottom)Remarks
1(Push ((First opening bracket
2(Push (( (Second opening bracket
32Ignore( (Not a bracket
4+Ignore( (Not a bracket
53Ignore( (Not a bracket
6)Pop → matches ((Closing bracket matches the top (
7*Ignore(Not a bracket
8(Push (( (New opening bracket
94Ignore( (Not a bracket
10/Ignore( (Not a bracket
112Ignore( (Not a bracket
12)Pop → matches ((Closing bracket matches the top (
13)Pop → matches ((empty)Closing bracket matches the remaining (
14+Ignore(empty)Not a bracket
152Ignore(empty)Not a bracket

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