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Q.Sodium metal crystallises in the cubic lattice and edge of the unit cell is 430 pm. Calculate the number of atoms in the unit cell. (Density of sodium = 0.9623 g.cm^-3, At wt. = 23, Avogadro No. NA = 6.023 x 10^23)

Uttar Pradesh UpmspUP Board (UPMSP) Intermediate 2019Subjective· 2mImportance★★★★★
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Using d = ZM/(NA a^3), Z comes out to about 2, so there are 2 atoms per unit cell (bcc).

Data: edge a = 430 pm = 4.30 x 10^-8 cm, density d = 0.9623 g cm^-3, M = 23 g mol^-1, NA = 6.023 x 10^23 mol^-1.

Density formula:

d = (Z x M) / (NA x a^3)

So Z = (d x NA x a^3) / M.

Step 1 - Volume of the unit cell:

a^3 = (4.30 x 10^-8)^3 = 79.507 x 10^-24 = 7.9507 x 10^-23 cm^3.

Step 2 - Substitute:

Z = (0.9623 x 6.023 x 10^23 x 7.9507 x 10^-23) / 23

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