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Q.At the same temperature, which pair of solutions is isotonic?

(a) 0.1 M NaCl0.1\,M\ NaCl and 0.1 M Na2SO40.1\,M\ Na_2SO_4
(b) 0.1 M0.1\,M urea and 0.1 M NaCl0.1\,M\ NaCl
(c) 0.1 M0.1\,M urea and 0.2 M MgCl20.2\,M\ MgCl_2
(d) 0.1 M Ca(NO3)20.1\,M\ Ca(NO_3)_2 and 0.1 M Na2SO40.1\,M\ Na_2SO_4
Uttar Pradesh UpmspUP Board (UPMSP) Intermediate 2020MCQ· 1mImportance★★★★★
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Isotonic ⇒ equal osmotic pressure ⇒ equal effective particle concentration i×Ci\times C; pair (d) both give 0.30.3.

Concept: Two solutions are isotonic when they exert the same osmotic pressure at the same temperature, π=i C RT\pi = i\,C\,RT. So we compare the effective molar concentration of particles =i×C= i\times C (where ii = number of ions per formula unit on complete dissociation).

  • (a) 0.1 NaCl0.1\,NaCl (i=2⇒0.2i=2\Rightarrow0.2) vs 0.1 Na2SO40.1\,Na_2SO_4 (i=3⇒0.3i=3\Rightarrow0.3) — unequal.
  • (b) 0.10.1 urea (i=1⇒0.1i=1\Rightarrow0.1) vs 0.1 NaCl0.1\,NaCl (i=2⇒0.2i=2\Rightarrow0.2) — unequal. …

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