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Examples A.1 · Example 9

Q.Every continuous function is differentiable. Examine whether this statement is true.

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The statement is false; the continuous function ϕ(x)=∣x∣\phi(x) = |x| is a counterexample — it is continuous everywhere but not differentiable at x=0x = 0.

Step 1 — Note why the claim is tempting.

Many familiar continuous functions are also differentiable everywhere, for example

f(x)=x2,g(x)=ex,h(x)=sin⁡x.f(x) = x^{2}, \qquad g(x) = e^{x}, \qquad h(x) = \sin x.

Each is continuous for all xx and differentiable for all xx, which might suggest that continuity always forces differentiability.

Step 2 — Choose a candidate counterexample.

Consider the modulus function

ϕ(x)=∣x∣={x,x≥0−x,x<0.\phi(x) = |x| = \begin{cases} x, & x \ge 0 \\ -x, & x < 0 \end{cases}.

It is continuous everywhere, including at x=0x = 0, since lim⁡x→0∣x∣=0=ϕ(0)\lim\limits_{x \to 0} |x| = 0 = \phi(0).

Step 3 — Test differentiability at x=0x = 0.

Examine the difference quotient from each side:

Right derivative: lim⁡h→0+∣0+h∣−∣0∣h=lim⁡h→0+hh=1,\text{Right derivative: } \lim_{h \to 0^{+}} \frac{|0+h| - |0|}{h} = \lim_{h \to 0^{+}} \frac{h}{h} = 1,

Left derivative: lim⁡h→0−∣0+h∣−∣0∣h=lim⁡h→0−−hh=−1.\text{Left derivative: } \lim_{h \to 0^{-}} \frac{|0+h| - |0|}{h} = \lim_{h \to 0^{-}} \frac{-h}{h} = -1. …

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