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Q.A die is thrown once. The number on the die is a multiple of 33 is denoted by EE, and the number on the die is even is denoted by FF. Are EE and FF independent events?

Uttar Pradesh UpmspUP Board (UPMSP) Intermediate 2024Subjective· 2mImportance★★★★★
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Concept understanding — Event Independence

Event Independence

Two events are independent when the occurrence of one does not change the probability of the other. Toss a coin and roll a die: the coin landing heads tells you nothing about whether the die shows a six. Contrast this with drawing cards without replacement, where the first draw does change the odds for the second — those events are dependent.

From Conditional Probability to a Clean Test

"Knowing BB doesn't change AA" means P(A∣B)=P(A)P(A \mid B) = P(A). Substituting the definition P(A∣B)=P(A∩B)P(B)P(A \mid B) = \dfrac{P(A \cap B)}{P(B)} and clearing the fraction gives the symmetric form used in practice:

P(A∩B)=P(A) P(B).P(A \cap B) = P(A)\,P(B).

Events AA and BB are independent exactly when the probability of both occurring equals the product of their individual probabilities. This version is preferred because it needs no non-zero condition and treats AA and BB alike.

A Quick Check

Roll a fair die. Let A={2,4,6}A = \{2,4,6\} (even) and B={4,5,6}B = \{4,5,6\} (greater than 3). Then P(A)=P(B)=12P(A) = P(B) = \tfrac{1}{2}, and A∩B={4,6}A \cap B = \{4,6\} so P(A∩B)=13P(A \cap B) = \tfrac{1}{3}. Since 13≠12⋅12=14\tfrac{1}{3} \neq \tfrac{1}{2} \cdot \tfrac{1}{2} = \tfrac{1}{4}, these events are not independent.

Three or More Events

Events A,B,CA, B, C are mutually independent only if all four conditions hold: the three pairwise products and

P(A∩B∩C)=P(A) P(B) P(C).P(A \cap B \cap C) = P(A)\,P(B)\,P(C).

Pairwise independence alone is not enough to guarantee mutual independence. …

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