Skip to content

Physics · Ch 4 — Moving Charges and Magnetism

Magnetic Field on the Axis of a Circular Current Loop

4.5

Magnetic Field on the Axis of a Circular Current Loop

Why the Field Points Along the Axis

A circular current loop produces a magnetic field that is symmetric about its axis. For any small current element IdlI d\mathbf{l} on the loop, the Biot-Savart law gives a field contribution dBd\mathbf{B} that is perpendicular to both dld\mathbf{l} and the displacement vector r\mathbf{r} from the element to the point on the axis.

Because the loop is symmetric, the components of dBd\mathbf{B} perpendicular to the axis cancel in pairs (e.g., from diametrically opposite elements). Only the component along the axis survives. The net field B\mathbf{B} at a point on the axis is therefore directed along the axis itself.


Derivation of the Magnetic Field

Consider a circular loop of radius RR carrying a steady current II, lying in the yzyz-plane with its centre at the origin OO. The xx-axis is the axis of the loop. Let PP be a point on this axis at a distance xx from OO.

  1. Biot-Savart law for a current element For a small element dld\mathbf{l} on the loop, the magnitude of the magnetic field at PP is

dB=μ04πI ∣dl×r∣r3dB = \frac{\mu_0}{4\pi} \frac{I \, |d\mathbf{l} \times \mathbf{r}|}{r^3}

where r\mathbf{r} is the vector from the element to PP, and r=∣r∣r = |\mathbf{r}|.

  1. Geometry of the loop

    • The distance from any element to PP is r=x2+R2r = \sqrt{x^2 + R^2}.
    • Every element dld\mathbf{l} is perpendicular to r\mathbf{r} (since dld\mathbf{l} lies in the yzyz-plane and r\mathbf{r} has components in the xzxz- or yzyz-plane). Hence ∣dl×r∣=r dl|d\mathbf{l} \times \mathbf{r}| = r \, dl.

    Therefore,

dB=μ04πI dlx2+R2dB = \frac{\mu_0}{4\pi} \frac{I \, dl}{x^2 + R^2}

  1. Component along the axis From the geometry, the angle θ\theta between r\mathbf{r} and the axis satisfies

cos⁡θ=Rx2+R2\cos\theta = \frac{R}{\sqrt{x^2 + R^2}}

The axial component of dBdB is

dBx=dBcos⁡θ=μ04πI dlx2+R2⋅Rx2+R2=μ04πIR dl(x2+R2)3/2dB_x = dB \cos\theta = \frac{\mu_0}{4\pi} \frac{I \, dl}{x^2 + R^2} \cdot \frac{R}{\sqrt{x^2 + R^2}} = \frac{\mu_0}{4\pi} \frac{I R \, dl}{(x^2 + R^2)^{3/2}}

  1. Integrate over the entire loop Summing dldl around the loop gives the circumference: ∮dl=2πR\oint dl = 2\pi R. The net magnetic field at PP is

B=∮dBx=μ04πIR(x2+R2)3/2⋅2πRB = \oint dB_x = \frac{\mu_0}{4\pi} \frac{I R}{(x^2 + R^2)^{3/2}} \cdot 2\pi R

Thus,

B=μ0IR22(x2+R2)3/2 i^\boxed{\mathbf{B} = \frac{\mu_0 I R^2}{2 (x^2 + R^2)^{3/2}} \, \hat{\mathbf{i}}}

where i^\hat{\mathbf{i}} is the unit vector along the axis (direction given by the right-hand thumb rule).


Special Case: Field at the Centre …

Figure 4.9Magnetic field on the axis of a current carrying circular loop of radius R. Shown are the magnetic field dB (due to a line element dl) and its components along and perpendicular to the axis.
Fig. 4.9 — Magnetic field on the axis of a current carrying circular loop of radius R. Shown are the magnetic field dB (due to a line element dl) and its components along and perpendicular to the axis.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

The figure shows a circular loop of radius RR lying in the Y–Z plane, with its centre at the origin OO. The X-axis is the axis of the loop, pointing to the right. The loop carries a steady current II (direction indicated by arrows on the loop). A point PP is marked on the X-axis at a distance xx from OO.

Two specific current elements are highlighted:

  • A line element dld\mathbf{l} at the top of the loop (in the Y–Z plane).
  • Another dld\mathbf{l} diametrically opposite at the bottom of the loop.

From the top dld\mathbf{l}, a displacement vector r\mathbf{r} (shown in blue) runs to point PP. The magnitude of r\mathbf{r} is r=x2+R2r = \sqrt{x^2 + R^2}.

At point PP, the magnetic field dBd\mathbf{B} due to the top dld\mathbf{l} is drawn perpendicular to r\mathbf{r} (as required by the Biot–Savart law). This dBd\mathbf{B} is then resolved into two components:

  • dBxdB_x — along the X-axis (to the right).
  • dB⊥dB_\perp — perpendicular to the X-axis (vertical up).

The angle θ\theta is marked at PP between dBd\mathbf{B} and dBxdB_x. From geometry, cos⁡θ=Rx2+R2\cos\theta = \frac{R}{\sqrt{x^2 + R^2}}.

The key physical idea is that the perpendicular components dB⊥dB_\perp from diametrically opposite elements cancel (the bottom element gives a dB⊥dB_\perp pointing vertically down, cancelling the top one). Only the axial components dBxdB_x add up, giving a net field along the X-axis.

The textbook derives the net magnetic field on the axis using this figure:

dB=μ04πI dlr2=μ04πI dlx2+R2dB = \frac{\mu_0}{4\pi} \frac{I\, dl}{r^2} = \frac{\mu_0}{4\pi} \frac{I\, dl}{x^2 + R^2}

Since dl⊥rd\mathbf{l} \perp \mathbf{r}, ∣dl×r∣=r dl|d\mathbf{l} \times \mathbf{r}| = r\, dl. The axial component is dBx=dBcos⁡θdB_x = dB \cos\theta, so:

dBx=μ04πI dlx2+R2⋅Rx2+R2=μ04πIR dl(x2+R2)3/2dB_x = \frac{\mu_0}{4\pi} \frac{I\, dl}{x^2 + R^2} \cdot \frac{R}{\sqrt{x^2 + R^2}} = \frac{\mu_0}{4\pi} \frac{I R\, dl}{(x^2 + R^2)^{3/2}}

Integrating dldl around the loop (circumference 2πR2\pi R) gives the final formula:

B=μ0IR22(x2+R2)3/2 i^\mathbf{B} = \frac{\mu_0 I R^2}{2(x^2 + R^2)^{3/2}} \,\hat{\mathbf{i}}

where: …

Figure 4.10The magnetic field lines for a current loop. The direction of the field is given by the right-hand thumb rule described in the text. The upper side of the loop may be thought of as the north pole and the lower side as the south pole of a magnet.
Fig. 4.10 — The magnetic field lines for a current loop. The direction of the field is given by the right-hand thumb rule described in the text. The upper side of the loop may be thought of as the north pole and the lower side as the south pole of a magnet.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What the figure shows

The figure depicts a single horizontal current loop — drawn as a flat ring or ellipse — carrying a steady current. Arrows on the loop indicate the direction of the current. Around the loop, blue magnetic field lines form closed loops that thread through the ring: they emerge upward from the top of the loop, fan outward, curve around the sides, and re-enter the bottom of the loop. This pattern is identical to the field of a bar magnet. The upper side of the loop is labelled as the north pole and the lower side as the south pole. Below the loop, a small stylised right hand is shown with fingers curled in the direction of the current and the thumb pointing upward — illustrating the right-hand thumb rule for the direction of the magnetic field.

Physical idea taught

The figure teaches that a current-carrying circular loop behaves like a magnetic dipole. The magnetic field lines are closed loops, just like those of a bar magnet. The direction of the field at any point is given by the right-hand thumb rule: if you curl the fingers of your right hand in the direction of the current, your thumb points in the direction of the magnetic field (out of the north pole). This analogy helps visualise the field pattern and understand that the loop has a north pole (where field lines emerge) and a south pole (where field lines re-enter).

Key formula developed with this figure

The textbook derives the magnetic field on the axis of a circular current loop using the Biot-Savart law. For a loop of radius RR carrying current II, the magnetic field at a point PP on the axis at distance xx from the centre is:

B=μ0IR22(x2+R2)3/2 i^\mathbf{B} = \frac{\mu_0 I R^2}{2 (x^2 + R^2)^{3/2}} \, \hat{\mathbf{i}}

where:

  • μ0\mu_0 is the permeability of free space (4π×10−7 T m/A4\pi \times 10^{-7} \, \text{T m/A})
  • II is the steady current in the loop
  • RR is the radius of the loop
  • xx is the distance from the centre of the loop along the axis
  • i^\hat{\mathbf{i}} is the unit vector along the axis (direction given by the right-hand thumb rule)

At the centre of the loop (x=0x = 0), the formula simplifies to: …