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Worked Examples · Example 13.4

Q.Answer the following questions:

(a) Are the equations of nuclear reactions (such as those given in Section 13.7) 'balanced' in the sense a chemical equation (e.g., 2H2+O2→2H2O2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}) is? If not, in what sense are they balanced on both sides?
(b) If both the number of protons and the number of neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice-versa) in a nuclear reaction?
(c) A general impression exists that mass-energy interconversion takes place only in nuclear reaction and never in chemical reaction. This is strictly speaking, incorrect. Explain.
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Nuclear reactions balance nucleon number and charge, not chemical species; mass-energy equivalence (E=mc2E=mc^2) accounts for the tiny mass defect that appears as energy, and this same principle applies — though far less noticeably — to chemical reactions as well.


(a) Balancing in nuclear vs. chemical equations

A chemical equation like 2H2+O2→2H2O2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O} balances atoms and charge — the same number of each element appears on both sides. The molecules themselves rearrange, but the atoms are conserved.

A nuclear reaction equation, such as

714N+24He→817O+11H{}^{14}_{7}\text{N} + {}^{4}_{2}\text{He} \rightarrow {}^{17}_{8}\text{O} + {}^{1}_{1}\text{H}

does not balance in the chemical sense — the elements on the left and right are different. Nitrogen and helium become oxygen and hydrogen. What is conserved are two quantities:

  1. Mass number (nucleon number) — the superscripts: 14+4=17+114 + 4 = 17 + 1
  2. Atomic number (proton number / charge) — the subscripts: 7+2=8+17 + 2 = 8 + 1

So a nuclear equation is balanced in terms of total nucleons and total charge, not in terms of chemical species. The identity of the nucleus changes, but the building blocks (protons and neutrons) are simply rearranged.

Watch out

A common mistake is to think that "mass" is conserved in nuclear reactions. The mass number (nucleon count) is conserved, but the actual mass (in kg or u) is not — the mass defect is the source of the released energy.


(b) If nucleons are conserved, where does the energy come from?

If the number of protons and neutrons is the same on both sides, you might wonder: how can mass be converted into energy? The key is that the total mass of the separated nucleons is not the same as the mass of the nucleus they form.

A nucleus is held together by the strong nuclear force. To pull it apart into individual protons and neutrons, you must supply energy — this energy is stored as the binding energy of the nucleus. Conversely, when nucleons fuse, they release that binding energy.

Because of Einstein’s relation E=mc2E = mc^2, this binding energy corresponds to a mass defect:

Δm=Zmp+Nmn−mnucleus\Delta m = Z m_p + N m_n - m_{\text{nucleus}}

where Δm>0\Delta m > 0 for a stable nucleus. The mass of the nucleus is less than the sum of the masses of its constituents.

In a nuclear reaction, the total number of nucleons is conserved, but the binding energy per nucleon differs between the reactants and products. If the products have a higher binding energy per nucleon (i.e., they are more tightly bound), the total mass of the products is slightly less than that of the reactants. The missing mass appears as kinetic energy of the products (or as gamma radiation), according to E=Δm c2E = \Delta m \, c^2.

Q=(mass of reactants−mass of products) c2Q = (\text{mass of reactants} - \text{mass of products}) \, c^2

The QQ-value of a nuclear reaction is the energy released (positive for exothermic reactions).

So mass is not "destroyed" — it is converted into energy, and the nucleon count remains unchanged. The mass defect is a measure of the binding energy difference.


(c) Mass-energy interconversion in chemical reactions

It is a widespread misconception that E=mc2E=mc^2 only matters in nuclear physics. In truth, every exothermic chemical reaction also involves a tiny mass decrease.

When hydrogen burns:

2H2+O2→2H2O+energy2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O} + \text{energy} …

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