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NCERT Exemplar · Q13

Q.Nuclei with magic no. of proton Z=2,8,20,28,50,82Z = 2, 8, 20, 28, 50, 82 and magic no. of neutrons N=2,8,20,28,50,82N = 2, 8, 20, 28, 50, 82 and 126126 are found to be very stable.

(i) Verify this by calculating the proton separation energy SpS_p for 120Sn^{120}\text{Sn} (Z=50Z = 50) and 121Sb^{121}\text{Sb} (Z=51Z = 51). The proton separation energy for a nuclide is the minimum energy required to separate the least tightly bound proton from a nucleus of that nuclide. It is given by Sp=(MZ−1, N+MH−MZ,N)c2S_p = (M_{Z-1,\,N} + M_H - M_{Z,N})c^2. Given 119In=118.9058 u^{119}\text{In} = 118.9058\ u, 120Sn=119.902199 u^{120}\text{Sn} = 119.902199\ u, 121Sb=120.903824 u^{121}\text{Sb} = 120.903824\ u, 1H=1.0078252 u^{1}\text{H} = 1.0078252\ u.
(ii) What does the existence of magic number indicate?
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Sp(120Sn)≈10.64 MeVS_p(^{120}\text{Sn}) \approx 10.64\ \text{MeV} versus Sp(121Sb)≈5.78 MeVS_p(^{121}\text{Sb}) \approx 5.78\ \text{MeV}: it takes nearly twice the energy to pull a proton out of the magic-ZZ tin nucleus, confirming that magic numbers mark closed, unusually stable nuclear shells.

What SpS_p measures

The proton separation energy is the least energy needed to knock the most loosely bound proton out of a nucleus. A larger SpS_p means a more tightly bound, more stable nucleus. The given formula is just conservation of mass-energy:

Sp=(MZ−1, N+MH−MZ,N)c2,S_p = (M_{Z-1,\,N} + M_H - M_{Z,N})c^2,

where MZ−1,NM_{Z-1,N} is the daughter (one fewer proton, same NN), MHM_H is the hydrogen-atom mass supplying the removed proton, and MZ,NM_{Z,N} is the parent. Using atomic masses, the MHM_H term automatically balances the electrons. Convert with 1 u=931.5 MeV/c21\ \text{u} = 931.5\ \text{MeV}/c^2.

(i) 120Sn^{120}\text{Sn} (Z=50Z=50, N=70N=70) — magic proton number

Removing a proton leaves 119In^{119}\text{In} (Z=49Z=49, N=70N=70):

Δ=M(119In)+MH−M(120Sn)=118.9058+1.0078252−119.902199.\Delta = M(^{119}\text{In}) + M_H - M(^{120}\text{Sn}) = 118.9058 + 1.0078252 - 119.902199.

118.9058+1.0078252=119.9136252,119.9136252−119.902199=0.0114262 u.118.9058 + 1.0078252 = 119.9136252,\quad 119.9136252 - 119.902199 = 0.0114262\ \text{u}.

Sp=0.0114262×931.5≈10.64 MeV.S_p = 0.0114262 \times 931.5 \approx 10.64\ \text{MeV}.

Comparison nucleus 121Sb^{121}\text{Sb} (Z=51Z=51, N=70N=70)

Removing a proton leaves 120Sn^{120}\text{Sn} (Z=50Z=50, N=70N=70):

Δ=M(120Sn)+MH−M(121Sb)=119.902199+1.0078252−120.903824.\Delta = M(^{120}\text{Sn}) + M_H - M(^{121}\text{Sb}) = 119.902199 + 1.0078252 - 120.903824.

119.902199+1.0078252=120.9100242,120.9100242−120.903824=0.0062002 u.119.902199 + 1.0078252 = 120.9100242,\quad 120.9100242 - 120.903824 = 0.0062002\ \text{u}.

Sp=0.0062002×931.5≈5.78 MeV.S_p = 0.0062002 \times 931.5 \approx 5.78\ \text{MeV}.

Compare

NucleusSpS_p (MeV)
120Sn^{120}\text{Sn} (Z=50Z=50, magic)≈10.64\approx 10.64
121Sb^{121}\text{Sb} (Z=51Z=51)≈5.78\approx 5.78

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