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Worked Examples · Example 8.13

Q.The following query displays details of all those employees whose name starts with 'K'.

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Employees whose name starts with 'K'.

SELECT * FROM EMPLOYEE WHERE Ename LIKE 'K%';

Output:

+-------+---------+--------+-------+--------+
| EmpNo | Ename   | Salary | Bonus | DeptId |
+-------+---------+--------+-------+--------+ …

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