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Exercises · 9.10

Q.Why is benzene extra ordinarily stable though it contains three double bonds?

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Benzene’s extraordinary stability comes from delocalisation of its six π-electrons into a continuous ring-shaped molecular orbital, which lowers its energy far below that of a hypothetical “cyclohexatriene” with three isolated double bonds. This stabilisation is quantified by a resonance energy of about 150 kJ/mol.


1. The puzzle: three double bonds, but not like alkenes

If you look at benzene’s structure — a six-carbon ring with alternating single and double bonds — you might expect it to behave like three ethene molecules stuck together. Ethene adds bromine instantly; benzene does not. Ethene is easily hydrogenated; benzene requires a catalyst and high pressure. Something is fundamentally different.

The key is that benzene’s double bonds are not localised between specific carbon pairs. The true structure is a resonance hybrid of two Kekulé structures, but even that description understates the reality.

Watch out

A common mistake is to think benzene “flips” between two Kekulé structures. It does not. The molecule has a single, static structure where all six C–C bonds are identical — intermediate between a single and a double bond (bond length ≈ 139 pm, compared to 154 pm for a C–C single bond and 134 pm for a C=C double bond).


2. The real picture: a delocalised π-system

Each carbon in benzene is sp2sp^2 hybridised. That leaves one unhybridised pzp_z orbital perpendicular to the ring plane. These six pzp_z orbitals overlap sideways with their neighbours, forming a continuous ring of electron density above and below the plane.

The six π-electrons are not confined to any one C–C pair. They are delocalised over the entire ring. This delocalisation is the source of stability.

The stabilisation energy of benzene relative to a hypothetical “cyclohexatriene” with localised double bonds is called its resonance energy:

ΔHresonance≈150 kJ mol−1\Delta H_{\text{resonance}} \approx 150\ \text{kJ mol}^{-1}

This is the extra energy you would need to “break” the delocalisation and force the electrons into three fixed double bonds.


3. How do we know this? Experimental evidence

The stability is not just theoretical. Three classic experiments confirm it:

  1. Hydrogenation enthalpy: Hydrogenating cyclohexene (one double bond) releases about 120 kJ/mol. If benzene had three isolated double bonds, you would expect 3×120=3603 \times 120 = 360 kJ/mol. The actual hydrogenation enthalpy of benzene to cyclohexane is only about 208 kJ/mol. The difference — roughly 152 kJ/mol — is the resonance energy.

  2. Bond lengths: X-ray diffraction shows all six C–C bonds are identical at 139 pm. No alternating short (double) and long (single) bonds are seen.

  3. Chemical inertness: Benzene undergoes substitution (electrophilic aromatic substitution) rather than addition. Addition would destroy the delocalised π-system; substitution preserves it. This preference is a direct consequence of the stabilisation.

Tip

A quick way to remember: benzene’s resonance energy (~150 kJ/mol) is roughly the energy of one strong covalent bond. That is why benzene resists addition reactions — you would lose that stabilisation.


4. The Hückel rule: why six π-electrons is special

Benzene’s stability is not just about delocalisation — it is about the number of π-electrons. The Hückel rule states that planar, monocyclic, fully conjugated systems are aromatic (extraordinarily stable) when they contain 4n+24n+2 π-electrons, where nn is a non-negative integer. …

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