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Worked Examples · Example 1

Q.If (x+1, y−2)=(3,1)(x + 1,\ y - 2) = (3, 1), find the values of xx and yy.

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Ordered pairs are equal only when their corresponding components match. Setting x+1=3x+1 = 3 and y−2=1y-2 = 1 gives x=2x = 2 and y=3y = 3.

The idea is simple but powerful: an ordered pair is defined by the order of its entries. When we say (a,b)=(c,d)(a, b) = (c, d), it means the first component equals the first component, and the second equals the second. There is no cross-matching or mixing — order is everything.

This is the definition of equality of ordered pairs. It’s the foundation for coordinate geometry, relations, and functions. Once you internalise that, the problem becomes a straightforward pair of linear equations.

  1. Match the first components. The first entry of (x+1,y−2)(x+1, y-2) is x+1x+1. The first entry of (3,1)(3, 1) is 33. So we must have:

x+1=3x + 1 = 3

  1. Solve for xx. Subtract 11 from both sides:

x=2x = 2

  1. Match the second components. The second entry of (x+1,y−2)(x+1, y-2) is y−2y-2. The second entry of (3,1)(3, 1) is 11. So:

y−2=1y - 2 = 1

  1. Solve for yy. Add 22 to both sides:

y=3y = 3

Watch out

A common mistake is to mix the components — for example, setting x+1=1x+1 = 1 or y−2=3y-2 = 3. Remember: first with first, second with second. The order in the pair is not interchangeable.

Tip

This same logic extends to ordered triples, quadruples, and so on. For (a,b,c)=(p,q,r)(a, b, c) = (p, q, r), you get three equations: a=pa=p, b=qb=q, c=rc=r. The pattern is always the same — match position by position.

✓Final answer

The values are x=2x = 2 and y=3y = 3.

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