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Exercise 2.2 · Q4

Q.An arrow diagram relates two sets. Set P={5,6,7}P = \{5, 6, 7\} and set Q={3,4,5}Q = \{3, 4, 5\}. An arrow is drawn from each element of PP to exactly one element of QQ as follows: 55 is joined to 33, 66 is joined to 44, and 77 is joined to 55. Write this relation

(i) in set-builder form,
(ii) in roster form. What is its domain and range?
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The arrow diagram joins 5→35\to 3, 6→46\to 4 and 7→57\to 5. In each pair the second number is 22 less than the first, so the rule is y=x−2y = x - 2. Written in roster form R={(5,3),(6,4),(7,5)}R = \{(5,3),(6,4),(7,5)\}, with domain {5,6,7}\{5,6,7\} and range {3,4,5}\{3,4,5\}.

Concept

A relation from a set PP to a set QQ is any subset of the Cartesian product P×QP \times Q; it can be listed as a set of ordered pairs (roster form) or described by a common rule the pairs obey (set-builder form). The domain is the set of all first coordinates that actually appear, and the range is the set of all second coordinates that actually appear.

Reading the arrows

Here P={5,6,7}P = \{5, 6, 7\} and Q={3,4,5}Q = \{3, 4, 5\}. The arrows give the ordered pairs

5→3,6→4,7→5.5 \to 3,\qquad 6 \to 4,\qquad 7 \to 5.

Finding the rule

Compare each first element with its image:

5−3=2,6−4=2,7−5=2.5 - 3 = 2,\qquad 6 - 4 = 2,\qquad 7 - 5 = 2.

Every pair satisfies x−y=2x - y = 2, i.e. y=x−2y = x - 2.

(i) Set-builder form …

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