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NCERT Exemplar · Q42

Q.If the variance of a data is 121, then the standard deviation of the data is _______.

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The standard deviation is the positive square root of the variance. Given a variance of 121, the standard deviation is 11\boxed{11}.

When we analyze a set of data, we often want to understand not just its central tendency (like the mean), but also how spread out the data points are. This spread or dispersion is crucial for understanding the variability within the data. Two common measures for this are variance and standard deviation.

Variance (σ2\sigma^2) quantifies the average squared difference of each data point from the mean. While it's a powerful mathematical tool, its units are the square of the original data units, which can make it difficult to interpret directly in the context of the original data. For example, if your data is in meters, the variance will be in square meters.

Standard deviation (σ\sigma) addresses this interpretability issue. It is simply the positive square root of the variance. By taking the square root, the standard deviation returns to the original units of the data, making it much easier to understand the typical deviation of data points from the mean. A larger standard deviation indicates greater spread in the data, while a smaller one indicates data points are clustered closer to the mean.

The standard deviation (σ\sigma) is the positive square root of the variance (σ2\sigma^2):

σ=σ2\sigma = \sqrt{\sigma^2}

Let's apply this concept to the given problem.

  1. Identify the given information: We are given that the variance of the data is 121. So, σ2=121\sigma^2 = 121. …

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