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Physics · Ch 1 — Electric Charges and Fields

Summary

Summary

  • Coulomb’s Law: Force between two point charges q1q_1 and q2q_2 separated by distance rr in vacuum is F=14πε0q1q2r2F = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r^2}, where 14πε0=9×109 N m2/C2\frac{1}{4\pi\varepsilon_0} = 9 \times 10^9 \, \text{N m}^2/\text{C}^2. Force is along the line joining charges, attractive for opposite signs, repulsive for like signs.

  • Electric Field: Field at a point is force per unit positive test charge: E⃗=F⃗q0\vec{E} = \frac{\vec{F}}{q_0}. For a point charge qq, E⃗=14πε0qr2r^\vec{E} = \frac{1}{4\pi\varepsilon_0} \frac{q}{r^2} \hat{r}.

  • Superposition Principle: Net force or field due to multiple charges is the vector sum of individual contributions.

  • Electric Field Lines: Start at positive charges, end at negative charges; never cross; tangent gives field direction; density indicates field strength.

  • Electric Dipole: Two equal and opposite charges +q+q and −q-q separated by distance 2a2a. Dipole moment p⃗=q⋅2ap^\vec{p} = q \cdot 2a \hat{p} (from −q-q to +q+q).

  • Field of a Dipole:

    • On axial line: Eaxial=14πε02pr3E_{\text{axial}} = \frac{1}{4\pi\varepsilon_0} \frac{2p}{r^3} (for r≫ar \gg a).
    • On equatorial line: Eequatorial=14πε0pr3E_{\text{equatorial}} = \frac{1}{4\pi\varepsilon_0} \frac{p}{r^3} (for r≫ar \gg a).
  • Torque on a Dipole in Uniform Field: τ⃗=p⃗×E⃗\vec{\tau} = \vec{p} \times \vec{E}, magnitude τ=pEsin⁡θ\tau = pE \sin\theta. Potential energy U=−p⃗⋅E⃗U = -\vec{p} \cdot \vec{E}.

  • Gauss’s Law: Total electric flux through a closed surface equals 1ε0\frac{1}{\varepsilon_0} times the net charge enclosed: ∮E⃗⋅dS⃗=qencε0\oint \vec{E} \cdot d\vec{S} = \frac{q_{\text{enc}}}{\varepsilon_0}.

  • Applications of Gauss’s Law:

    • Field due to an infinite line charge: E=λ2πε0rE = \frac{\lambda}{2\pi\varepsilon_0 r}.
    • Field due to an infinite plane sheet: E=σ2ε0E = \frac{\sigma}{2\varepsilon_0} (independent of distance). …