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Exercises · 2.10

Q.A 12 pF12\ \text{pF} capacitor is connected to a 50 V50\ \text{V} battery. How much electrostatic energy is stored in the capacitor?

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The electrostatic energy stored in a capacitor is given by U=12CV2U = \frac{1}{2} C V^2. For C=12 pFC = 12\ \text{pF} and V=50 VV = 50\ \text{V}, the energy is 1.5×10−8 J1.5 \times 10^{-8}\ \text{J}.

The key idea here is that a capacitor stores energy in the electric field between its plates. When you connect it to a battery, work is done to move charge onto the plates, and that work gets stored as electrostatic potential energy. The formula U=12CV2U = \frac{1}{2} C V^2 comes directly from the fact that the voltage across the capacitor builds up linearly as charge accumulates — the average voltage during charging is half the final voltage, so the energy is half the product of final charge and final voltage.

Let’s work through it step by step.

  1. Identify the given quantities.

    The capacitance is C=12 pFC = 12\ \text{pF}. Remember, 1 pF=10−12 F1\ \text{pF} = 10^{-12}\ \text{F}, so C=12×10−12 FC = 12 \times 10^{-12}\ \text{F}.

    The voltage of the battery is V=50 VV = 50\ \text{V}. This is the potential difference the battery maintains across the capacitor once fully charged.

  2. Recall the formula for electrostatic energy stored in a capacitor.

    There are three equivalent forms, depending on which variables you know:

U=12CV2=12QV=Q22CU = \frac{1}{2} C V^2 = \frac{1}{2} Q V = \frac{Q^2}{2C}

Since we have CC and VV directly, the first form is the most convenient.

U=12CV2U = \frac{1}{2} C V^2

  1. Substitute the values.

U=12×(12×10−12)×(50)2U = \frac{1}{2} \times (12 \times 10^{-12}) \times (50)^2

First, square the voltage: 502=250050^2 = 2500.

Then multiply:

U=12×12×10−12×2500U = \frac{1}{2} \times 12 \times 10^{-12} \times 2500

Simplify step by step:

12×12=6\frac{1}{2} \times 12 = 6, so

U=6×10−12×2500U = 6 \times 10^{-12} \times 2500

Now 6×2500=150006 \times 2500 = 15000, so

U=15000×10−12 JU = 15000 \times 10^{-12}\ \text{J}

  1. Express in scientific notation. 15000=1.5×10415000 = 1.5 \times 10^4, so U=1.5×104×10−12=1.5×10−8 JU = 1.5 \times 10^4 \times 10^{-12} = 1.5 \times 10^{-8}\ \text{J} …

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