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Q.State and prove Ampere's circuital law.

Uttarakhand UbseUttarakhand Board Intermediate (Class 12) 2023Subjective· 3mImportance★★★★★
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Ampere's circuital law: the line integral of B⃗\vec B around a closed loop equals μ0\mu_0 times the enclosed current; proved for a long straight wire.

Statement: The line integral of the magnetic field B⃗\vec{B} around any closed loop is equal to μ0\mu_0 times the total current IencI_{enc} enclosed/threading through that loop:

∮B⃗⋅dl⃗=μ0Ienc\oint \vec{B}\cdot d\vec{l} = \mu_0 I_{enc}

Proof (for a long straight current-carrying wire): Consider an infinite straight conductor carrying current II. By symmetry, the magnetic field lines are concentric circles around the wire, and at every point on a circle of radius rr centred on the wire, BB has the same magnitude and is tangential to the circle (parallel to dl⃗d\vec l everywhere on this Amperian loop).

Using the Biot-Savart law, the field at distance rr from such a wire is known to be B=μ0I2πrB = \dfrac{\mu_0 I}{2\pi r}.

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