Q.Write a program to input line(s) of text from the user until enter is pressed. Count the total number of characters in the text (including white spaces),total number of alphabets, total number of digits, total number of special symbols and total number of words in the given text. (Assume that each word is separated by one space).

Classify every character of the input with the string methods isalpha()/isdigit(), and count words as space-separated pieces:

text = input("Enter the text: ")
alphabets = digits = special = 0
for ch in text:
    if ch.isalpha():
        alphabets += 1
    elif ch.isdigit():
        digits += 1
    elif ch != ' ':
        special += 1
words = len(text.split(' ')) if text else 0
print("Total characters (with spaces):", len(text))
print("Total alphabets:", alphabets)
print("Total digits:", digits)
print("Total special symbols:", special)
print("Total words:", words)

Enter the text: Hello World 123 @#
Total characters (with spaces): 18
Total alphabets: 10
Total digits: 3
Total special symbols: 2
Total words: 4

Idea. input() reads characters until Enter is pressed — that gives us the text. Then this is a pure counting problem: walk the string once and put every character into exactly one bucket — alphabet, digit, or special symbol (we treat the space as a word separator, not a special symbol). Words need no second pass: since the problem guarantees each word is separated by one space, splitting on the space counts them.

Algorithm

1. Read text with input().
2. Set counters alphabets = digits = special = 0.
3. For each character: isalpha() → alphabet; else isdigit() → digit; else if it is not a space → special symbol.
4. Total characters = len(text) (spaces included automatically).
5. Words = len(text.split(' ')) — with one space between words, this equals number of words (guard the empty string with 0).

text = input("Enter the text: ")

alphabets = digits = special = 0
for ch in text:
    if ch.isalpha():
        alphabets += 1
    elif ch.isdigit():
        digits += 1
    elif ch != ' ':
        special += 1

words = len(text.split(' ')) if text else 0

print("Total characters (with spaces):", len(text))
print("Total alphabets:", alphabets)
print("Total digits:", digits)
print("Total special symbols:", special)
print("Total words:", words)

Sample run — count it by hand to verify: "Hello World 123 @#" has 5+1+5+1+3+1+2 = 18 characters; letters H-e-l-l-o-W-o-r-l-d = 10; digits 1-2-3 = 3; specials @ and # = 2; pieces "Hello"/"World"/"123"/"@#" = 4 words.

Enter the text: Hello World 123 @#
Total characters (with spaces): 18
Total alphabets: 10
Total digits: 3
Total special symbols: 2
Total words: 4

The loop is O(n) — one look at each character.