Skip to content
Question 25 of 25

Q.(i) The outermost electronic configuration of the atom of an element is 3s²3p³. Mention the position of the element in the long periodic table.

(ii) Why is electron gain enthalpy of oxygen less than that of sulphur? [1 + 2]
West Bengal WbchseWest Bengal HS First Year (WBCHSE Class XI) Annual Examination 2018Subjective· 3mImportance★★★★★
100% · 25/25 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The outer configuration ns2np3ns^2np^3 identifies Group 15, and the principal quantum number n=3n=3 fixes Period 3; oxygen's smaller size (versus sulphur) makes adding an extra electron less energetically favourable.

(i) Position in the periodic table: the outermost configuration 3s23p33s^2 3p^3 has:

  • Principal quantum number n=3n = 3 → Period 3.
  • Total valence electrons =2+3=5= 2 + 3 = 5, with the np3np^3 pattern → Group 15 (the nitrogen family). This element is phosphorus (P).

(ii) Why electron gain enthalpy of O is less negative than that of S: oxygen is much smaller than sulphur (O is in period 2, S in period 3). When an extra electron is added to the already compact 2p2p subshell of oxygen, it experiences significant electron–electron repulsion from the existing electrons packed into that small volume, making the process less energetically favourable (less negative electron gain enthalpy) than expected.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.