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Q.Which of the following compounds does not produce a white precipitate on treatment with ammoniacal silver nitrate solution?

(a) Acetylene
(b) Methyl acetylaene
(c) Ethyl acetylene
(d) Dimethyl acetylene
West Bengal WbchseWest Bengal HS First Year (WBCHSE Class XI) Annual Examination 2018MCQ· 1mImportance★★★★★est
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Only a terminal alkyne (one with a ≡C-H\equiv C\text{-}H) can form a silver acetylide precipitate with ammoniacal AgNO3AgNO_3; an internally-substituted (non-terminal) alkyne cannot.

Ammoniacal silver nitrate reacts specifically with terminal alkynes (alkynes with a ≡C-H\equiv C\text{-}H at the end of the chain), because the triple-bond hydrogen is weakly acidic and is displaced by Ag+Ag^+, forming an insoluble white/grey silver acetylide precipitate:

R-C≡CH+[Ag(NH3)2]+→R-C≡C-Ag↓+NH3+NH4+R\text{-}C\equiv CH + [Ag(NH_3)_2]^+ \rightarrow R\text{-}C\equiv C\text{-}Ag\downarrow + NH_3 + NH_4^+

Check each option:

  • Acetylene, HC≡CHHC\equiv CH — terminal on both ends → gives precipitate.
  • Methyl acetylene, CH3-C≡CHCH_3\text{-}C\equiv CH — terminal → gives precipitate. …

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