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Chemistry · Ch 7 — p-Block Elements (Groups 13-14)

Boron Oxide and Boric Acid

7.3

Boron Oxide and Boric Acid

Boron's principal oxide, boron oxide (B2O3\text{B}_2\text{O}_3), is formed by strongly heating boric acid or boron itself in air/oxygen. Structurally it is a covalent network solid built from planar BO3\text{BO}_3 triangular units (boron is sp2sp^2 hybridised, three-coordinate) linked together through shared bridging oxygen atoms into a disordered, glass-forming network; this is why B2O3\text{B}_2\text{O}_3 is the key glass-former in borosilicate glass. Like most oxides of the lighter p-block elements, B2O3\text{B}_2\text{O}_3 is acidic — it dissolves in water to regenerate boric acid, and reacts with basic oxides/hydroxides to form borates.

Orthoboric acid, B(OH)3\text{B(OH)}_3 (commonly written H3BO3\text{H}_3\text{BO}_3), is the hydrated form obtained when borax is treated with a mineral acid. Its structure is planar: each boron atom is sp2sp^2 hybridised and surrounded by three −OH-\text{OH} groups at the corners of a triangle, and these planar B(OH)3\text{B(OH)}_3 units stack into two-dimensional sheets held together by extensive hydrogen bonding between the −OH-\text{OH} groups of neighbouring molecules, giving boric acid its characteristic soft, flaky, layered crystalline habit — broadly analogous to graphite's layered structure, though held by hydrogen bonds rather than delocalised π\pi bonding.

Boric acid is described as a weak, monobasic acid, but — unusually — it does not ionise by donating a proton the way a typical Brønsted acid does. Boron in B(OH)3\text{B(OH)}_3 has only six electrons around it (three σ\sigma bonds, no lone pair), leaving an empty 2p2p orbital that makes the boron atom electron-deficient and hence a good Lewis acid (electron-pair acceptor). In water, B(OH)3\text{B(OH)}_3 acts on this Lewis acidity: rather than releasing H+\text{H}^+ itself, it accepts a hydroxide ion (the electron pair) from a water molecule, releasing a proton from that water molecule in the process:

B(OH)3+2H2O⇌[B(OH)4]−+H3O+\text{B(OH)}_3 + 2\text{H}_2\text{O} \rightleftharpoons [\text{B(OH)}_4]^{-} + \text{H}_3\text{O}^{+} …