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Chemistry · Ch 8 — Thermodynamics

The Born-Haber Cycle

8.8

The Born-Haber Cycle

The Born-Haber cycle, named after Max Born and Fritz Haber, is a specific and especially important application of Hess's law that breaks down the formation of an ionic solid from its constituent elements into a sequence of separate, individually measurable enthalpy steps. Its principal use is to calculate lattice enthalpy — the enthalpy released when a mole of ionic solid forms from its gaseous ions (or, equivalently, the energy needed to separate a mole of solid completely into gaseous ions) — a quantity that cannot be measured directly in the laboratory, since gaseous ions cannot simply be combined and observed forming a crystal under controlled calorimetric conditions.

For a general ionic solid MX(s)\text{MX}(s) formed from a metal M\text{M} and a non-metal X2\text{X}_2, the cycle connects the elements in their standard states to the solid compound through five conceptual steps, forming a closed thermochemical loop:

  1. Sublimation of the solid metal to gaseous atoms: M(s)→M(g)\text{M}(s) \rightarrow \text{M}(g), enthalpy ΔsubH\Delta_{sub}H (endothermic).
  2. Ionization of the gaseous metal atoms: M(g)→M+(g)+e−\text{M}(g) \rightarrow \text{M}^+(g) + e^-, enthalpy = ionization enthalpy (endothermic).
  3. Dissociation of the gaseous non-metal molecule into atoms: 12X2(g)→X(g)\tfrac{1}{2}\text{X}_2(g) \rightarrow \text{X}(g), enthalpy = half the bond dissociation enthalpy (endothermic).
  4. Electron gain by the gaseous non-metal atoms: X(g)+e−→X−(g)\text{X}(g) + e^- \rightarrow \text{X}^-(g), enthalpy = electron gain enthalpy (usually exothermic for a first electron gain, though often endothermic overall for a second, as with oxide ion formation).
  5. Lattice formation, combining the gaseous ions into the solid crystal: M+(g)+X−(g)→MX(s)\text{M}^+(g) + \text{X}^-(g) \rightarrow \text{MX}(s), enthalpy = −(lattice enthalpy)-(\text{lattice enthalpy}) (strongly exothermic).

Because enthalpy is a state function, the sum of these five step enthalpies must exactly equal the directly measurable standard enthalpy of formation of the compound, ΔfH∘\Delta_f H^\circ, giving the working equation of the cycle:

ΔfH∘=ΔsubH+(ionization enthalpy)+12(bond dissociation enthalpy)+(electron gain enthalpy)+(−lattice enthalpy)\Delta_f H^\circ = \Delta_{sub}H + (\text{ionization enthalpy}) + \tfrac{1}{2}(\text{bond dissociation enthalpy}) + (\text{electron gain enthalpy}) + (-\text{lattice enthalpy}) …

Figure 1Born-Haber energy-level cycle for sodium chloride, showing sublimation, ionization, dissociation, electron gain and lattice enthalpy as a closed thermochemical loop

What this figure shows. An enthalpy-level (energy-cycle) diagram for the formation of NaCl(s)\text{NaCl}(s) from Na(s)\text{Na}(s) and 12Cl2(g)\tfrac{1}{2}\text{Cl}_2(g), drawn as a closed loop of upward and downward arrows at increasing height: starting at Na(s)+12Cl2(g)\text{Na}(s) + \tfrac{1}{2}\text{Cl}_2(g), an upward arrow for sublimation of Na(s)\text{Na}(s) to Na(g)\text{Na}(g), a further upward arrow for dissociation of 12Cl2(g)\tfrac{1}{2}\text{Cl}_2(g) to Cl(g)\text{Cl}(g), a further upward arrow for ionization of Na(g)\text{Na}(g) to Na+(g)+e−\text{Na}^+(g) + e^-, a downward arrow for electron gain by Cl(g)\text{Cl}(g) to Cl−(g)\text{Cl}^-(g), reaching the gaseous-ion level Na+(g)+Cl−(g)\text{Na}^+(g) + \text{Cl}^-(g), then a large downward arrow labelled lattice enthalpy to the solid NaCl(s)\text{NaCl}(s) at the bottom, with a single direct downward arrow on the left labelled ΔfH∘\Delta_f H^\circ connecting the starting elements directly to NaCl(s)\text{NaCl}(s), closing the cycle. …