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Mathematics · Ch 4 — Complex Numbers and Quadratic Equations

Modulus and Argument of a Complex Number

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Modulus and Argument of a Complex Number

Modulus and Argument of a Complex Number

Modulus. For z=a+ibz=a+ib, the modulus of zz, written ∣z∣|z| (also called rr), is defined as

∣z∣=a2+b2.|z|=\sqrt{a^2+b^2}.

Geometrically, ∣z∣|z| is the length OPOP of the segment from the origin to the point P(a,b)P(a,b) representing zz in the Argand plane: dropping perpendiculars from PP to each axis forms a right triangle with legs ∣a∣|a| and ∣b∣|b|, so OP=a2+b2OP=\sqrt{a^2+b^2} by Pythagoras — exactly the modulus. Because it is a square root of a sum of squares, the modulus is always a non-negative real number, and ∣z∣=0|z|=0 exactly when z=0z=0 (both a=0a=0 and b=0b=0).

Standard properties (each provable from the definition and the algebra of §2):

  • ∣z∣=∣zˉ∣|z|=|\bar z|, since a2+(−b)2=a2+b2a^2+(-b)^2=a^2+b^2.
  • zzˉ=∣z∣2z\bar z=|z|^2 (already met in §2.3).
  • ∣z1z2∣=∣z1∣ ∣z2∣|z_1z_2|=|z_1|\,|z_2| — the modulus of a product is the product of the moduli.
  • ∣z1z2∣=∣z1∣∣z2∣\left|\dfrac{z_1}{z_2}\right|=\dfrac{|z_1|}{|z_2|} for z2≠0z_2\neq0.

∣3−4i∣=32+(−4)2=9+16=25=5|3-4i|=\sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5.

Argument. The argument (also called the amplitude) of a non-zero z=a+ibz=a+ib, written θ=arg⁡(z)\theta=\arg(z), is the angle that the segment OPOP makes with the positive real axis, measured anticlockwise as positive. It satisfies

cos⁡θ=ar,sin⁡θ=br,tan⁡θ=ba (a≠0),where r=∣z∣.\cos\theta=\frac{a}{r}, \qquad \sin\theta=\frac{b}{r}, \qquad \tan\theta=\frac{b}{a}\ (a\neq0), \qquad \text{where } r=|z|.

A given z≠0z\neq0 has infinitely many possible arguments, differing by whole multiples of 2π2\pi (adding a full turn does not change the direction of OPOP); the one lying in the standard range (−π,π](-\pi,\pi] is called the principal argument.

Why the raw inverse tangent is not enough. The function tan⁡−1(b/a)\tan^{-1}(b/a) always returns a value strictly between −π/2-\pi/2 and π/2\pi/2, so it alone cannot distinguish a point in Quadrant I from the diametrically opposite point in Quadrant III (both give the same ratio b/ab/a), nor Quadrant II from Quadrant IV. The correct principal argument therefore needs a quadrant-by-quadrant correction to the raw tan⁡−1(b/a)\tan^{-1}(b/a) value, tabulated in the accompanying reference table for every quadrant and every axis. …

Table 1Argument of z = a + ib by quadrant / axis (principal value convention: -pi < theta <= pi)
Position of (a, b)Sign of a, btheta = arg(z)Worked example
Positive real axisa > 0, b = 0theta = 0z = 5, theta = 0
Quadrant Ia > 0, b > 0theta = tan^-1(b/a), in (0, pi/2)z = 1 + i, theta = pi/4
Positive imaginary axisa = 0, b > 0theta = pi/2z = 3i, theta = pi/2
Quadrant IIa < 0, b > 0theta = pi - tan^-1(b/a
Negative real axisa < 0, b = 0theta = piz = -6, theta = pi
Quadrant IIIa < 0, b < 0theta = -(pi - tan^-1(b/a