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Mathematics · Ch 10 — Sequence and Series

Geometric Progression

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Geometric Progression

A sequence a1,a2,a3,…a_1, a_2, a_3, \ldots (with every term nonzero) is called a Geometric Progression (G.P.) if the ratio of every pair of consecutive terms is the same constant, called the common ratio, usually denoted rr:

r=a2a1=a3a2=⋯=an+1anfor every n,r≠0.r = \frac{a_2}{a_1} = \frac{a_3}{a_2} = \cdots = \frac{a_{n+1}}{a_n} \quad \text{for every } n, \qquad r \ne 0.

If the first term is aa, the G.P. is written out as

a, ar, ar2, ar3, …a,\ ar,\ ar^2,\ ar^3,\ \ldots

so that each term is obtained from the previous one by multiplying by rr.

The nnth (general) term. Reading off the pattern, the first term needs rr multiplied in 00 times, the second needs it 11 time, and in general the nnth term needs rr multiplied in (n−1)(n-1) times:

an=arn−1.\boxed{a_n = ar^{n-1}}.

As with the A.P. formula, this follows by induction: true for n=1n=1 (giving a1=aa_1=a), and if an=arn−1a_n=ar^{n-1} then an+1=an⋅r=arn−1⋅r=arna_{n+1}=a_n\cdot r = ar^{n-1}\cdot r = ar^n, matching the formula at n+1n+1.

Sum of the first nn terms — derivation by "multiply and subtract". Let

Sn=a+ar+ar2+⋯+arn−1,r≠1.S_n = a+ar+ar^2+\cdots+ar^{n-1}, \qquad r \ne 1.

Multiply every term by rr:

rSn=ar+ar2+ar3+⋯+arn−1+arn.rS_n = ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n.

Now subtract the second equation from the first. Every middle term — ar,ar2,…,arn−1ar, ar^2, \ldots, ar^{n-1} — appears in both expressions and cancels exactly, leaving only the first term of the first line and the last term of the second line:

Sn−rSn=a−arn⟹Sn(1−r)=a(1−rn)⟹Sn=a(1−rn)1−r(r≠1).S_n - rS_n = a - ar^n \quad\Longrightarrow\quad S_n(1-r) = a(1-r^n) \quad\Longrightarrow\quad \boxed{S_n = \frac{a(1-r^n)}{1-r}} \quad (r\ne 1).

Equivalently, multiplying numerator and denominator by −1-1, this is often written Sn=a(rn−1)r−1S_n=\dfrac{a(r^n-1)}{r-1} — both forms are identical and either may be used; the second is usually more convenient when r>1r>1, since it avoids a negative numerator and denominator both. …