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Physics · Ch 4 — Laws of Motion

Equilibrium of Concurrent Forces

4.8

Equilibrium of Concurrent Forces

Several forces are said to be concurrent when the lines along which they act all pass through one single common point, even though the forces themselves may point in entirely different directions. A point acted on by a number of concurrent forces is in equilibrium exactly when the vector sum of all those forces is zero -- equivalently, when the forces, drawn one after another (head to tail, in any order) as vectors, form a closed polygon with no gap left between the start of the first vector and the end of the last.

For the particular case of exactly three concurrent forces PP, QQ and RR keeping a point in equilibrium, this closed-polygon condition becomes a closed triangle, and it can be restated as Lami's theorem: each force is proportional to the sine of the angle between the other two forces. Labelling α\alpha as the angle between QQ and RR (i.e. opposite PP in the force triangle), β\beta as the angle between RR and PP (opposite QQ), and γ\gamma as the angle between PP and QQ (opposite RR), with α+β+γ=360∘\alpha + \beta + \gamma = 360^\circ,

Psin⁡α=Qsin⁡β=Rsin⁡γ\frac{P}{\sin\alpha} = \frac{Q}{\sin\beta} = \frac{R}{\sin\gamma}

Lami's theorem is especially convenient because it lets any one of the three forces be found directly from the other two and the angles between them, without first having to resolve every force into horizontal and vertical components -- though resolving into components (setting ∑Fx=0\sum F_x = 0 and ∑Fy=0\sum F_y = 0 separately) always works too, and gives exactly the same answer, since Lami's theorem is nothing more than a restated, purely geometric form of that same vector equilibrium condition. …

Figure 1Three concurrent forces in equilibrium at a point (Lami's theorem construction)

What this figure shows. A single point OO with three force vectors PP, QQ and RR drawn radiating outward from it in three different directions, with the three angles between consecutive pairs of vectors marked as α\alpha (the angle between QQ and RR, opposite PP), β\beta (the angle between RR and PP, opposite QQ) and γ\gamma (the angle between PP and QQ, opposite RR), the three angles together making a full 360^\\circ around the point. Alongside this, a second, separate diagram redraws the same three vectors placed head-to-tail in sequence, forming a closed triangle with no gap -- the visual condition for the point to be in equilibrium, and the geometric basis of Lami's relation $\dfrac{P}{\sin\alpha} = \dfrac …