Physics · Ch 2 — Motion in a Straight Line
Kinematic Equations for Uniformly Accelerated Motion
Kinematic Equations for Uniformly Accelerated Motion
For the common and important special case of uniformly accelerated motion — motion in which the acceleration has one constant value throughout the interval considered — three standard relations connect initial velocity , final velocity , displacement , acceleration and time . As required by the WBCHSE syllabus, we derive all three both graphically (from the v-t graph of Section 2.7) and by calculus (by integrating the defining relations and ).
First equation:
Graphical derivation. On a v-t graph, a body with constant acceleration has a straight-line graph of constant slope , starting at when . The slope of a straight line equals (rise)/(run), so
Calculus derivation. Since is constant, can be directly integrated with respect to time from to (with velocity going from to ):
Second equation:
Graphical derivation. From Section 2.7, displacement equals the area under the v-t graph — here a trapezium with parallel sides and , and width :
Calculus derivation. Since and, from the first equation, , we integrate position from (taken as the origin, ) as runs from to :
This is also, as noted in Section 2.6, exactly why the position-time graph of uniformly accelerated motion is a parabola: is a quadratic function of .
Third equation:
Graphical derivation. Eliminate between the first two equations: from we get ; substituting into and simplifying algebraically gives .
Calculus derivation (chain rule). Using and the chain rule , we can write the constant acceleration as , i.e. . Integrating both sides — position from to , and velocity from to :
(This chain-rule derivation is worked out in full generality in Numerical 4.) …
| t (s) | v = u + at (m/s) | s = ut + ½at² (m) |
|---|---|---|
| 0 | 0 | 0 |
| 1 | 4 | 2 |
| 2 | 8 | 8 |
| 3 | 12 | 18 |