Skip to content

Physics · Ch 5 — Work, Energy and Power

Work Done by a Constant Force

5.2

Work Done by a Constant Force

When a constant force F⃗\vec F acts on a body while the body undergoes a displacement d⃗\vec d, the work done by that force is defined as the scalar (dot) product of the two vectors:

W=F⃗⋅d⃗=Fdcos⁡θW = \vec F \cdot \vec d = Fd\cos\theta

where F=∣F⃗∣F = |\vec F|, d=∣d⃗∣d = |\vec d|, and θ\theta is the angle between the direction of the force and the direction of the displacement. Because work is a dot product of two vectors, it is itself a pure number (a scalar) -- it has a magnitude but no direction of its own, even though both of the quantities that produced it, force and displacement, are vectors. The SI unit of work is the joule (J\text{J}), defined as 1 J=1 N⋅m1\ \text{J} = 1\ \text{N}\cdot\text{m}: the work done when a force of 1 newton1\ \text{newton} moves its point of application through 1 metre1\ \text{metre} in the direction of the force.

The factor cos⁡θ\cos\theta makes precise an idea that is intuitively obvious once stated: only the component of the force along the direction of motion contributes to the work done; any component of the force perpendicular to the displacement contributes nothing at all, however large that perpendicular component may be. Three special cases are worth fixing clearly:

  • When θ=0∘\theta = 0^\circ (force and displacement in the same direction), cos⁡θ=1\cos\theta = 1 and W=FdW = Fd, its largest possible positive value for the given FF and dd -- for example, gravity doing work on a freely falling body.
  • When θ=90∘\theta = 90^\circ (force perpendicular to displacement), cos⁡θ=0\cos\theta = 0 and W=0W = 0 -- for example, the normal reaction of a horizontal floor on a body sliding along it does zero work, however large the normal force, because the floor's push is always perpendicular to the body's horizontal motion; similarly, the centripetal force in uniform circular motion, always perpendicular to the instantaneous velocity, does zero work at every instant.
  • When θ=180∘\theta = 180^\circ (force directly opposing the displacement), cos⁡θ=−1\cos\theta = -1 and W=−FdW = -Fd, a negative quantity -- for example, kinetic friction opposing a sliding body's motion, or an applied braking force opposing a moving vehicle, both of which remove kinetic energy from the body rather than adding to it. …