Q.Find the maturity value of a Recurring Deposit of ₹200 per month for 24 months at 6% per annum.

Apply the standard RD maturity-value formula directly.

Here $P=₹200$, $r=6\%$ per annum, $n=24$ months.

Step 1 — Total instalments.

Step 2 — Interest earned.

$\frac{P\,r\,n(n+1)}{2400} = \frac{200\times6\times24\times25}{2400} = \frac{720{,}000}{2400} = ₹300$ …

Using $n=24$ but mistakenly treating the rate as if it were already a per-month rate (i.e. not needing the $\div1200$-style scaling built into the $2400$ divisor) leads to a wildly inflated interest figure — the formula's constant $2400$ already correctly combines the annual-t …