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Worked Examples · Example 4

Q.Form the differential equation representing the family of curves y=Ax+Bx2y = Ax + Bx^2, where AA and BB are arbitrary constants.

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The family y=Ax+Bx2y=Ax+Bx^2 has two arbitrary constants, so two differentiations are needed.

First derivative: dydx=A+2Bx\dfrac{dy}{dx} = A + 2Bx.

Second derivative: d2ydx2=2B\dfrac{d^2y}{dx^2} = 2B, so B=12d2ydx2B = \dfrac12\dfrac{d^2y}{dx^2}.

Substituting BB into the first-derivative equation: A=dydx−2Bx=dydx−xd2ydx2A = \dfrac{dy}{dx} - 2Bx = \dfrac{dy}{dx} - x\dfrac{d^2y}{dx^2}.

Substituting both AA and BB into the original relation y=Ax+Bx2y=Ax+Bx^2:

y=(dydx−xd2ydx2)x+12d2ydx2x2=xdydx−x2d2ydx2+12x2d2ydx2=xdydx−12x2d2ydx2y = \left(\dfrac{dy}{dx}-x\dfrac{d^2y}{dx^2}\right)x + \dfrac12\dfrac{d^2y}{dx^2}x^2 = x\dfrac{dy}{dx} - x^2\dfrac{d^2y}{dx^2} + \dfrac12 x^2\dfrac{d^2y}{dx^2} = x\dfrac{dy}{dx} - \dfrac12 x^2\dfrac{d^2y}{dx^2} …

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