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Worked Examples · Example 5

Q.Evaluate: 82/38^{2/3}.

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Route 1 — root first, then power:

82/3=(81/3)2=(83)2=22=48^{2/3} = \left(8^{1/3}\right)^2 = \left(\sqrt[3]{8}\right)^2 = 2^2 = 4

since 2×2×2=82\times2\times2=8, so 83=2\sqrt[3]{8}=2.

Route 2 — power first, then root (independent check):

82/3=(82)1/3=641/3=643=48^{2/3} = \left(8^2\right)^{1/3} = 64^{1/3} = \sqrt[3]{64} = 4 …

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