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Chemistry · Ch 8 — Chemical Kinetics

Temperature Dependence of the Rate of a Reaction: The Arrhenius Equation

8.10

Temperature Dependence of the Rate of a Reaction: The Arrhenius Equation

The Arrhenius equation. Svante Arrhenius proposed, on the basis of extensive

experimental measurements of how rate constants vary with temperature, that the rate constant kk of

almost every reaction obeys the relation

k=A e−Ea/RT\boxed{k = A\,e^{-E_a/RT}}

where EaE_a is the activation energy, RR is the universal gas constant (8.314 J K−1mol−18.314\ \text{J K}^{-1} \text{mol}^{-1}), TT is the absolute temperature, and AA is a constant for a given reaction called

the pre-exponential factor (or frequency factor) -- related, in the language of collision theory

(previous sections), to how often molecules collide and with what fraction of correct orientations, and

having the same units as the rate constant kk itself.

The exponential factor e−Ea/RTe^{-E_a/RT} is exactly the Boltzmann factor from collision theory: the

fraction of molecules, at temperature TT, whose energy exceeds the threshold EaE_a. Because this

factor rises exponentially, not linearly, with TT, even a modest increase in temperature produces a

large increase in kk -- exactly the strong temperature-sensitivity described qualitatively in the

section on factors affecting rate.

The logarithmic (linear) form. Taking the natural logarithm of both sides of the Arrhenius equation:

ln⁡k=ln⁡A−EaRT\ln k = \ln A - \frac{E_a}{RT}

or, converting to base-10 logarithms (dividing throughout by 2.3032.303):

log⁡k=log⁡A−Ea2.303 R T\log k = \log A - \frac{E_a}{2.303\,R\,T}

This is the equation of a straight line if log⁡k\log k is plotted against 1/T1/T: comparing with

y=mx+cy = mx + c, the slope of the line is −Ea/(2.303R)-E_a/(2.303R) and its yy-intercept (at 1/T=01/T = 0) is log⁡A\log A.

Measuring the rate constant kk of a reaction at several different temperatures and plotting

log⁡k\log k against 1/T1/T therefore gives a straight line whose slope directly yields the activation

energy, Ea=−2.303 R×slopeE_a = -2.303\,R \times \text{slope}, and whose intercept yields the pre-exponential factor …

Figure 1Arrhenius plot of $\ln k$ against $1/T$

What this figure shows. A graph with 1/T1/T (in K−1\text{K}^{-1}) on the horizontal axis and ln⁡k\ln k on the vertical axis. The plotted points, each obtained by measuring the rate constant kk of the same reaction at a different absolute temperature TT, fall on a single straight line with a negative slope: ln⁡k\ln k decreases steadily as 1/T1/T increases (i.e. as temperature falls). The line's slope equals −Ea/R-E_a/R, so a steeper downward slope corresponds to a larger activation energy EaE_a. Extending the straight line to the vertical axis (where 1/T=01/T = 0) gives a yy-intercept equal to ln⁡A\ln A, the natural logarithm of the Arrhenius pre-exponential factor. No curve, no scatter -- the entire point of plotting ln⁡k\ln k (rather than kk itself) aga …