Q.Which one of KCl and K2SO4 is very much active for the coagulation of Fe(OH)3 solution? Explain why. OR What is protective colloid? Write with an example.
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Start your 14-day free trial to unlock the full solution →Fe(OH)3 sol carries a positive charge, so it is coagulated by the anion of an added electrolyte; the anion with the higher charge is the more powerful coagulant (Hardy-Schulze rule).
Step 1 — Nature of the sol: Fe(OH)3 sol is a positively charged colloid (Fe3+ ions are preferentially adsorbed on the colloidal particles).
Step 2 — Hardy-Schulze rule: For coagulating a charged sol, the ion of the electrolyte carrying charge OPPOSITE to the sol is the effective ion, and its coagulating (flocculating) power increases sharply with its valency (roughly as the 6th power of valency).
Step 3 — Compare the two electrolytes:
- KCl supplies Cl^- (valency 1, univalent anion)
- K2SO4 supplies SO4^2- (valency 2, divalent anion) …
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