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Chemistry · Ch 12 — Organic Compounds Containing Nitrogen

Preparation of Cyanides and Isocyanides

12.12

Preparation of Cyanides and Isocyanides

Both cyanides and isocyanides are made from the identical starting material -- a

haloalkane -- and the identical pseudohalide ion, CN−\text{CN}^-; the ONLY variable that

decides which isomer forms is which METAL SALT supplies that cyanide ion, because

CN−\text{CN}^- is an ambident nucleophile capable of attacking through either its

carbon end or its nitrogen end.

With potassium cyanide, KCN\text{KCN} (predominantly IONIC in character, so the free

CN−\text{CN}^- ion reacts largely under thermodynamic/HSAB-type control): the more

electronegative, harder, more stable end of the anion -- carbon, which bears more of the

negative charge in the resonance structures of cyanide -- is the site that attacks the

electrophilic carbon of the haloalkane, giving the alkyl CYANIDE:

R−X+K+ CN−⟶R−C≡N+KX\text{R}-\text{X} + \text{K}^+\ \text{CN}^- \longrightarrow \text{R}-\text{C}{\equiv} \text{N} + \text{KX}

With silver cyanide, AgCN\text{AgCN} (predominantly COVALENT in character, because

silver is a soft, highly polarisable cation that binds strongly and covalently to the

carbon end of cyanide, effectively "using up" that end and leaving nitrogen as the more

available, more nucleophilic terminus): the reaction instead proceeds through the

NITROGEN end, giving the alkyl ISOCYANIDE:

R−X+AgCN⟶R−N≡C+AgX\text{R}-\text{X} + \text{AgCN} \longrightarrow \text{R}-\text{N}{\equiv}\text{C} + \text{AgX}

This is exactly the same "ionic vs. covalent salt decides which end of an ambident ion

reacts" logic already met for nitro compounds vs. nitrite esters (Section 25.3, …