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Question 56 of 65

Q.Evaluate lim(n→∞) [1²/(n³+1³) + 2²/(n³+2³) + ... + 1/2n].

West Bengal WbchseWest Bengal HS (WBCHSE) Board 2024Subjective· 4mImportance★★★★★
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Recognize the sum as a Riemann sum for a definite integral by writing the general term as 1n⋅(r/n)21+(r/n)3\frac1n\cdot\frac{(r/n)^2}{1+(r/n)^3}.

The sum is Sn=∑r=1nr2n3+r3\displaystyle S_n = \sum_{r=1}^{n} \frac{r^2}{n^3+r^3} (the last term, at r=nr=n, is n2n3+n3=12n\dfrac{n^2}{n^3+n^3}=\dfrac{1}{2n}, matching the last term given in the question).

Rewrite each term by dividing numerator and denominator by n3n^3:

r2n3+r3=1n⋅(r/n)21+(r/n)3\frac{r^2}{n^3+r^3} = \frac{1}{n}\cdot\frac{(r/n)^2}{1+(r/n)^3}

So Sn=1n∑r=1n(r/n)21+(r/n)3\displaystyle S_n = \frac1n\sum_{r=1}^n \frac{(r/n)^2}{1+(r/n)^3}, which is a Riemann sum for f(x)=x21+x3f(x)=\dfrac{x^2}{1+x^3} on [0,1][0,1] with x=r/nx=r/n. Hence:

lim⁡n→∞Sn=∫01x21+x3 dx\lim_{n\to\infty} S_n = \int_0^1 \frac{x^2}{1+x^3}\,dx

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