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Question 34 of 43

Q.Show that tan(π/4 + (1/2)cos⁻¹(a/b)) + tan(π/4 - (1/2)cos⁻¹(a/b)) = 2b/a.

West Bengal WbchseWest Bengal HS (WBCHSE) Board 2023Subjective· 4mImportance★★★★★
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Expand both tangents using the standard tan⁡(π/4±x)\tan(\pi/4\pm x) formulas in terms of t=tan⁡(12cos⁡−1ab)t=\tan\left(\tfrac12\cos^{-1}\tfrac ab\right), then use the half-angle cosine formula to simplify.

Step 1. Let θ=cos⁡−1ab\theta=\cos^{-1}\dfrac ab, so cos⁡θ=ab\cos\theta=\dfrac ab. Let t=tan⁡θ2t=\tan\dfrac\theta2.

Step 2. Use tan⁡ ⁣(π4+x)=1+tan⁡x1−tan⁡x\tan\!\left(\dfrac\pi4+x\right)=\dfrac{1+\tan x}{1-\tan x} and tan⁡ ⁣(π4−x)=1−tan⁡x1+tan⁡x\tan\!\left(\dfrac\pi4-x\right)=\dfrac{1-\tan x}{1+\tan x} with x=θ/2x=\theta/2:

tan⁡ ⁣(π4+θ2)+tan⁡ ⁣(π4−θ2)=1+t1−t+1−t1+t=(1+t)2+(1−t)21−t2=2(1+t2)1−t2.\tan\!\left(\frac\pi4+\frac\theta2\right)+\tan\!\left(\frac\pi4-\frac\theta2\right) = \frac{1+t}{1-t}+\frac{1-t}{1+t} = \frac{(1+t)^2+(1-t)^2}{1-t^2} = \frac{2(1+t^2)}{1-t^2}.

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