Skip to content
Question 32 of 51

Q.Show that A(2, 3, -4), B(1, -2, 3) and C(3, 8, -11) are collinear.

West Bengal WbchseWest Bengal HS (WBCHSE) Board 2019Subjective· 2mImportance★★★★★
63% · 32/51 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

If AC⃗\vec{AC} is a scalar multiple of AB⃗\vec{AB}, the three points lie on one line.

Given A(2,3,−4)A(2,3,-4), B(1,−2,3)B(1,-2,3), C(3,8,−11)C(3,8,-11).

AB⃗=B−A=(1−2, −2−3, 3−(−4))=(−1,−5,7)\vec{AB}=B-A=(1-2,\,-2-3,\,3-(-4))=(-1,-5,7)

AC⃗=C−A=(3−2, 8−3, −11−(−4))=(1,5,−7)\vec{AC}=C-A=(3-2,\,8-3,\,-11-(-4))=(1,5,-7)

Notice AC⃗=(1,5,−7)=−1⋅(−1,−5,7)=−AB⃗\vec{AC}=(1,5,-7)=-1\cdot(-1,-5,7)=-\vec{AB}.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.