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Physics · Ch 1 — Electric Charges and Fields

Coulomb's Law

1.3

Coulomb's Law

Charles Augustin de Coulomb measured, using a sensitive torsion balance, exactly how the force between two small charged spheres depends on their charge and their separation. His result, Coulomb's law, is the single most important quantitative law in electrostatics:

The force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of the two charges, and inversely proportional to the square of the distance between them; it acts along the straight line joining the two charges.

For two point charges q1q_1 and q2q_2 separated by distance rr, the magnitude of the force is

F=kq1q2r2,k=14πϵ0F = \frac{kq_1q_2}{r^2}, \qquad k=\frac{1}{4\pi\epsilon_0}

where ϵ0=8.854×10−12 C2N−1m−2\epsilon_0 = 8.854\times10^{-12}\ \text{C}^2\text{N}^{-1}\text{m}^{-2} is the permittivity of free space, and the combination k=1/4πϵ0≈9×109 N m2/C2k=1/4\pi\epsilon_0 \approx 9\times10^9\ \text{N}\,\text{m}^2/\text{C}^2 is the Coulomb constant. (Writing the constant as 1/4πϵ01/4\pi\epsilon_0 rather than simply as kk looks awkward here, but it is chosen deliberately so that the 4π4\pi cancels out neatly later, when Gauss's theorem is written for a sphere.) When the two charges sit in some other medium instead of vacuum, ϵ0\epsilon_0 is replaced by ϵ=ϵrϵ0\epsilon=\epsilon_r\epsilon_0, where ϵr\epsilon_r is the medium's relative permittivity (dielectric constant); the force is always weaker in a medium than in vacuum, since ϵr>1\epsilon_r>1 for every real material.

Written in full vector form, the force F⃗21\vec{F}_{21} exerted BY charge q1q_1 ON charge q2q_2, with r^21\hat{r}_{21} the unit vector pointing from q1q_1 to q2q_2, is

F⃗21=kq1q2r2r^21\vec{F}_{21} = \frac{kq_1q_2}{r^2}\hat{r}_{21}

The sign of the product q1q2q_1q_2 automatically fixes the direction: if q1q_1 and q2q_2 have the same sign, q1q2>0q_1q_2>0 and F⃗21\vec{F}_{21} points along +r^21+\hat{r}_{21}, i.e. away from q1q_1 -- a repulsive force; if they have opposite signs, q1q2<0q_1q_2<0 and F⃗21\vec{F}_{21} points along −r^21-\hat{r}_{21}, i.e. toward q1q_1 -- an attractive force. By Newton's third law, the force F⃗12\vec{F}_{12} that q2q_2 exerts back on q1q_1 is exactly equal in magnitude and opposite in direction: F⃗12=−F⃗21\vec{F}_{12} = -\vec{F}_{21}. …