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Physics · Ch 10 — Wave Optics

Path Difference, Phase Difference and Conditions for Maxima and Minima

10.7

Path Difference, Phase Difference and Conditions for Maxima and Minima

Let PP be a point on the screen at a distance yy from the central point OO, in a Young's double slit set-up with slit separation dd and screen distance D≫dD\gg d. Using this approximation, the two paths S1PS_1P and S2PS_2P are very nearly parallel, and simple geometry (dropping a perpendicular from S1S_1 onto S2PS_2P) gives the path difference between them as

Δ=S2P−S1P≈ydD\Delta=S_2P-S_1P\approx\frac{yd}{D}

The corresponding phase difference, since a path difference of one full wavelength λ\lambda corresponds to a phase difference of 2π2\pi, is ϕ=(2π/λ)Δ\phi=(2\pi/\lambda)\Delta.

If the two slits send out waves of equal amplitude and hence equal intensity I0I_0, the resultant intensity at PP, found by adding the two waves as phasors and squaring, works out to

I=4I0cos⁡2(ϕ/2)I=4I_0\cos^2(\phi/2) …

Table 1Conditions for bright and dark fringes in Young's double slit experiment
FringePath difference Δ\DeltaPhase difference ϕ\phiResultant intensity
Bright (constructive)nλn\lambda, n=0,±1,±2,…n=0,\pm1,\pm2,\ldots2nπ2n\piI=4I0I=4I_0 (maximum)