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Numerical Problems · Q9

Q.From the following data, calculate TC, AFC, AVC, AC and MC. TFC = ₹60 throughout. TVC at Q = 1, 2, 3, 4, 5 is ₹40, ₹70, ₹90, ₹100, ₹130 respectively.

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✓ Free question

Step 1 — Total Cost. TC=TFC+TVCTC = TFC + TVC at each output level (TFC = ₹60 throughout):

QTFCTVCTC
060060
16040100
26070130
36090150
460100160
560130190

Step 2 — Per-unit costs (AFC=TFC/QAFC=TFC/Q, AVC=TVC/QAVC=TVC/Q, AC=TC/QAC=TC/Q):

QAFCAVCAC
160.040.0100.0
230.035.065.0
320.030.050.0
415.025.040.0
512.026.038.0

(Check: AC=AFC+AVCAC = AFC+AVC at every Q, e.g. at Q=2, 30+35=6530+35=65 ✓.)

Step 3 — Marginal Cost (MCn=TCn−TCn−1MC_n = TC_n - TC_{n-1}):

QMC
1100−60 = 40
2130−100 = 30
3150−130 = 20
4160−150 = 10
5190−160 = 30

Dual-solve check: recomputing independently from the TVC column alone (since TFC is constant, MC also equals the change in TVC) gives the identical figures — 40, 30, 20, 10, 30 — confirming the TC-based computation.

Note that AFC falls continuously (60→12) as expected, while AVC and AC begin falling and are still falling at Q=5 in this particular data set — a longer schedule would eventually show MC rising past AC and pulling both AVC and AC back up, exactly as the Law of Variable Proportions predicts on the cost side.

✓Final answer

TC = 60, 100, 130, 150, 160, 190 (Q=0 to 5); AFC = 60, 30, 20, 15, 12; AVC = 40, 35, 30, 25, 26; AC = 100, 65, 50, 40, 38; MC = 40, 30, 20, 10, 30 (Q=1 to 5).

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