Q.Write the atomic number of the element present in the third period and seventeenth group of the periodic table.
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Start your 14-day free trial to unlock the full solution →The element in the third period and seventeenth group is chlorine. Its atomic number is 17, determined by adding the total electrons in the first three shells (2 + 8 + 7).
Element Nomenclature: Why Period and Group Tell You the Atomic Number
The periodic table is organised so that the period (row) tells you the number of electron shells, and the group (column) tells you the number of valence electrons (for main-group elements). For an element in the third period, electrons fill up to the third shell (). For group 17 (the halogens), the element has 7 valence electrons in its outermost shell.
To find the atomic number, you simply count the total electrons in a neutral atom:
- First shell (): holds a maximum of 2 electrons.
- Second shell (): holds a maximum of 8 electrons.
- Third shell (): for group 17, it contains 7 electrons (the valence shell is not full).
So the total electrons = . That is the atomic number.
A common mistake is to think the third shell can hold 18 electrons (its maximum capacity) and then add 7, giving 28 — but that would be the element nickel, which is in period 4, not period 3. The third period only fills the 3s and 3p orbitals; the 3d orbitals start filling only in period 4. So for period 3, the third shell holds at most 8 electrons (2 in 3s, 6 in 3p).
Step-by-Step Reasoning
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Identify the period.
The third period means the element has electrons in three principal shells: , , and .
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Identify the group.
Group 17 (halogens) means the element has 7 electrons in its outermost shell (the valence shell). For period 3, the outermost shell is .
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Fill the inner shells completely.
- Shell 1 (): maximum 2 electrons → .
- Shell 2 (): maximum 8 electrons → . Total so far: electrons.
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Place the valence electrons in the third shell. …
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