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Chemistry · Ch 6 — Equilibrium

Common Ion Effect in the Ionization of Acids and Bases

6.11.8

Common Ion Effect in the Ionization of Acids and Bases

The Common Ion Effect in Acid-Base Ionization

When a weak acid or weak base is placed in water, it establishes an equilibrium between the undissociated molecule and its ions. The position of this equilibrium is not fixed — it shifts in response to changes in concentration, just as Le Chatelier's principle predicts. The common ion effect is the name given to the shift that occurs when one of the ions already present in the equilibrium is added from an external source.

The Acetic Acid Example

Consider acetic acid, a weak monoprotic acid. Its dissociation equilibrium in water is:

CH3COOH(aq)⇌H+(aq)+CH3COO−(aq)\mathrm{CH_3COOH(aq) \rightleftharpoons H^+(aq) + CH_3COO^-(aq)}

or, using the shorthand notation HAc for acetic acid and Ac⁻ for acetate ion:

HAc(aq)⇌H+(aq)+Ac−(aq)\mathrm{HAc(aq) \rightleftharpoons H^+(aq) + Ac^-(aq)}

The acid dissociation constant for this equilibrium is:

Ka=[H+][Ac−][HAc]K_a = \frac{[\mathrm{H^+}][\mathrm{Ac^-}]}{[\mathrm{HAc}]}

At a given temperature, KaK_a is a fixed number. This means that if we change the concentration of any species in the expression, the other concentrations must adjust to keep the ratio constant.

What happens when acetate ions are added? Suppose we add sodium acetate (NaAc) to the solution. Sodium acetate dissociates completely, providing a large concentration of Ac⁻ ions. The equilibrium quotient [H+][Ac−]/[HAc][\mathrm{H^+}][\mathrm{Ac^-}]/[\mathrm{HAc}] temporarily exceeds KaK_a. To restore equilibrium, the system shifts to the left — more HAc is formed, consuming H⁺ and Ac⁻. The net result is a decrease in [H+][\mathrm{H^+}].

What happens when H⁺ ions are added? If we add a strong acid like HCl, the concentration of H⁺ rises sharply. Again, the quotient exceeds KaK_a, and the equilibrium shifts left, converting H⁺ and Ac⁻ into undissociated HAc. This reduces the concentration of free H⁺, though not back to its original value.

Watch out

The common ion effect does not change the value of KaK_a or KbK_b. It only shifts the equilibrium position. The equilibrium constant remains constant at a given temperature.

Why This Matters

The common ion effect is the fundamental principle behind buffer solutions. A buffer resists changes in pH because it contains both a weak acid and its conjugate base (or a weak base and its conjugate acid). When an external acid or base is added, the common ion effect shifts the equilibrium to consume most of the added H⁺ or OH⁻, keeping the pH nearly constant.

A Quantitative Look

Let's see how the common ion effect changes the pH of a weak acid solution. For a 0.10 M acetic acid solution alone, the equilibrium calculation gives:

Ka=1.8×10−5[H+]=Ka×C=1.8×10−5×0.10=1.34×10−3 MpH=−log⁡(1.34×10−3)=2.87\begin{aligned} K_a &= 1.8 \times 10^{-5} \\ [\mathrm{H^+}] &= \sqrt{K_a \times C} = \sqrt{1.8 \times 10^{-5} \times 0.10} = 1.34 \times 10^{-3} \text{ M} \\ \mathrm{pH} &= -\log(1.34 \times 10^{-3}) = 2.87 \end{aligned}

Now suppose we add enough sodium acetate to make the solution 0.10 M in Ac⁻ as well. Let xx be the concentration of H⁺ at equilibrium. The initial concentrations (after adding acetate but before any shift) are:

SpeciesInitial concentration (M)Change (M)Equilibrium concentration (M)
HAc0.10−x-x0.10−x0.10 - x
H⁺0+x+xxx
Ac⁻0.10+x+x0.10+x0.10 + x

Substitute into the KaK_a expression:

1.8×10−5=x(0.10+x)0.10−x1.8 \times 10^{-5} = \frac{x(0.10 + x)}{0.10 - x}

Because KaK_a is very small, xx will be much smaller than 0.10. We can approximate 0.10+x≈0.100.10 + x \approx 0.10 and 0.10−x≈0.100.10 - x \approx 0.10:

1.8×10−5=x(0.10)0.10=x1.8 \times 10^{-5} = \frac{x(0.10)}{0.10} = x

So x=1.8×10−5x = 1.8 \times 10^{-5} M, and pH=−log⁡(1.8×10−5)=4.74\mathrm{pH} = -\log(1.8 \times 10^{-5}) = 4.74.

Important

Adding the common ion (acetate) raised the pH from 2.87 to 4.74 — a decrease in H⁺ concentration by a factor of about 75. This is the common ion effect in action.

The General Principle

For any weak acid HA:

HA⇌H++A−\mathrm{HA \rightleftharpoons H^+ + A^-}

Adding A⁻ (from a salt like NaA) shifts the equilibrium left, decreasing [H⁺]. Adding H⁺ (from a strong acid) also shifts the equilibrium left, decreasing [A⁻] and increasing [HA]. …