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NCERT Exemplar · Q38

Q.Match the following equilibria with the corresponding condition.
Column I

(i) Liquid ⇌ Vapour
(ii) Solid ⇌ Liquid
(iii) Solid ⇌ Vapour
(iv) Solute (s) ⇌ Solute (solution)
Column II
(a) Saturated solution
(b) Boiling point
(c) Sublimation point
(d) Melting point
(e) Unsaturated solution
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The key idea is to match each phase or dissolution equilibrium with the specific temperature or concentration condition at which the two phases coexist in dynamic equilibrium. The correct matches are: (i)→(b), (ii)→(d), (iii)→(c), (iv)→(a).

Every equilibrium in Column I describes a situation where two forms of the same substance are in balance — the rate of forward change equals the rate of backward change. For a pure substance, such an equilibrium exists only at one particular temperature (for a given pressure), while for a solute dissolving, it exists at a specific concentration.

Let’s go through each one.

  1. Liquid ⇌ Vapour

    This is the equilibrium between a liquid and its vapour. At a fixed external pressure (usually 1 atm), this equilibrium occurs only at the boiling point — the temperature at which the vapour pressure of the liquid equals the surrounding pressure. Below that temperature, the liquid is stable; above it, the vapour dominates. So (i) matches with (b) Boiling point.

  2. Solid ⇌ Liquid

    This is the melting/freezing equilibrium. At a given pressure, a pure solid and its liquid coexist only at the melting point (also called the freezing point). At this temperature, the solid and liquid phases have the same Gibbs free energy. So (ii) matches with (d) Melting point.

  3. Solid ⇌ Vapour

    Some solids (like camphor, iodine, dry ice) can go directly from solid to vapour without passing through the liquid phase. This is sublimation. The temperature at which the solid and vapour coexist in equilibrium (at a given pressure) is the sublimation point. So (iii) matches with (c) Sublimation point.

  4. Solute (s) ⇌ Solute (solution) …

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