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NCERT Exemplar · Q19

Q.PbO and PbO2 react with HCl according to following chemical equations :
2PbO + 4HCl → 2PbCl2 + 2H2O
PbO2 + 4HCl → PbCl2 + Cl2 + 2H2O
Why do these compounds differ in their reactivity?

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The difference in reactivity arises from the stability of the +2 oxidation state of lead. PbO (Pb in +2 state) is stable and simply undergoes acid-base neutralisation, while PbO₂ (Pb in +4 state) is a strong oxidising agent that gets reduced to Pb²⁺, oxidising Cl⁻ to Cl₂.

Why the difference? The concept of oxidation state stability

Lead is a heavy element in Group 14. Down the group, the inert pair effect becomes pronounced — the two s-electrons in the outermost shell become increasingly reluctant to participate in bonding. For lead, the +2 oxidation state is far more stable than the +4 state. PbO₂ is therefore a strong oxidising agent: it wants to gain two electrons and drop to the more stable Pb²⁺.

This is the key. PbO already has lead in its stable +2 state, so it behaves as a normal basic oxide. PbO₂, with lead in the unstable +4 state, will oxidise anything it can — including chloride ions from HCl.

Let's walk through each reaction.


1. PbO + HCl — a simple acid-base reaction

PbO is a basic oxide. It contains Pb²⁺, which is already in its most stable oxidation state. When treated with HCl, the oxide ion (O²⁻) simply accepts protons:

PbO+2HCl→PbCl2+H2O\text{PbO} + 2\text{HCl} \rightarrow \text{PbCl}_2 + \text{H}_2\text{O}

The balanced equation given is just twice this:

2PbO+4HCl→2PbCl2+2H2O2\text{PbO} + 4\text{HCl} \rightarrow 2\text{PbCl}_2 + 2\text{H}_2\text{O}

No change in oxidation state occurs. Pb remains +2, Cl remains –1, H remains +1, O remains –2. This is a straightforward neutralisation — no redox.

Tip

If you ever see a metal oxide reacting with an acid to give a salt and water only, it's almost certainly a non-redox acid-base reaction. Check the oxidation states to confirm.


2. PbO₂ + HCl — a redox reaction driven by the instability of Pb⁴⁺

Now look at PbO₂. Lead is in the +4 state here — much less stable than +2. The Pb⁴⁺ ion is a strong oxidising agent. It wants to gain two electrons and become Pb²⁺.

Where can it get those electrons? From the chloride ions (Cl⁻) in HCl. Chloride can be oxidised to chlorine gas (Cl₂).

Let's track the changes:

  • Reduction half: Pb⁴⁺ + 2e⁻ → Pb²⁺
  • Oxidation half: 2Cl⁻ → Cl₂ + 2e⁻

Combine them:

PbO2+4HCl→PbCl2+Cl2+2H2O\text{PbO}_2 + 4\text{HCl} \rightarrow \text{PbCl}_2 + \text{Cl}_2 + 2\text{H}_2\text{O}

Notice that only two of the four chloride ions get oxidised to Cl₂. The other two remain as Cl⁻ in PbCl₂. The water comes from the oxide ions combining with H⁺.

Watch out

A common mistake is to think that all four HCl molecules participate in the redox. They don't — only two provide electrons for the reduction of Pb⁴⁺. The other two simply provide Cl⁻ to balance the charge as PbCl₂.


3. Why doesn't PbO also produce Cl₂?

Because PbO already has lead in its stable +2 state. There is no driving force for it to accept electrons. It has no tendency to oxidise Cl⁻. So the reaction stops at simple salt formation. …

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