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Miscellaneous Exercise · Q1

Q.2≤3x−4≤52 \le 3x - 4 \le 5

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✓ Free question

A compound inequality chains two conditions on the same variable; solve each piece separately, then intersect the results. Here xx lies in [2,3]\boxed{[2, 3]}.

Why compound inequalities work this way

When you see 2≤3x−4≤52 \le 3x - 4 \le 5, you're really reading two statements at once: "3x−43x - 4 is at least 22" and "3x−43x - 4 is at most 55." The solution set is every xx that satisfies both conditions simultaneously. The cleanest route is to isolate xx by performing identical operations on all three parts of the chain, preserving the inequality signs as long as we avoid multiplying or dividing by a negative number.

Step-by-step solution

1. Add 44 to every part.

We want to peel away the "−4-4" from 3x3x. Adding 44 throughout keeps the inequalities balanced:

2+4≤3x−4+4≤5+42 + 4 \le 3x - 4 + 4 \le 5 + 4

6≤3x≤96 \le 3x \le 9

2. Divide every part by 33.

Now isolate xx by dividing through by 33. Since 3>03 > 0, the inequality directions stay the same:

63≤3x3≤93\frac{6}{3} \le \frac{3x}{3} \le \frac{9}{3}

2≤x≤32 \le x \le 3

3. Interpret the result.

This tells us xx must lie between 22 and 33, inclusive of both endpoints. In interval notation, that's [2,3][2, 3].

Tip

You can always check boundary and interior points: x=2x = 2 gives 3(2)−4=23(2) - 4 = 2 ✓, x=3x = 3 gives 3(3)−4=53(3) - 4 = 5 ✓, and x=2.5x = 2.5 gives 3(2.5)−4=3.53(2.5) - 4 = 3.5, which lies in [2,5][2, 5] ✓.

Watch out

Had we needed to multiply or divide by a negative number, every inequality sign would flip. For instance, if the middle term were −3x+4-3x + 4, dividing by −3-3 would reverse both ≤\le symbols.

✓Final answer

The solution is 2≤x≤3\boxed{2 \le x \le 3}, or in interval notation [2,3][2, 3].

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