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Worked Examples · Example 9

Q.Let A={1,2}A = \{1, 2\} and B={3,4}B = \{3, 4\}. Find the number of relations from AA to BB.

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A relation from AA to BB is any subset of the Cartesian product A×BA \times B; since ∣A×B∣=4|A \times B| = 4, the number of relations is 24=162^4 = \boxed{16}.

Understanding Relations Through Cartesian Products

A relation from set AA to set BB is fundamentally a way of pairing elements from AA with elements from BB. Formally, it's any subset of the Cartesian product A×BA \times B.

The Cartesian product A×BA \times B consists of all ordered pairs (a,b)(a, b) where a∈Aa \in A and b∈Bb \in B. For our sets:

A×B={(1,3),(1,4),(2,3),(2,4)}A \times B = \{(1,3), (1,4), (2,3), (2,4)\}

This gives us four possible ordered pairs. A relation is formed by choosing which of these pairs to include. We might include all of them, none of them, or any combination in between.

Counting the Relations

  1. Count the elements in A×BA \times B

    Since AA has 2 elements and BB has 2 elements, the Cartesian product has ∣A∣×∣B∣=2×2=4|A| \times |B| = 2 \times 2 = 4 ordered pairs.

  2. Recognize that each relation is a subset

    A relation from AA to BB is any subset of A×BA \times B. For each of the 4 ordered pairs, we face a binary choice: include it in our relation or exclude it.

  3. Apply the subset-counting principle …

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