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Miscellaneous Exercise · Q2

Q.If f(x)=x2f(x) = x^2, find f(1.1)−f(1)(1.1−1)\dfrac{f(1.1) - f(1)}{(1.1 - 1)}.

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✓ Free question

The expression is the difference quotient of f(x)=x2f(x)=x^2 at x=1x=1 with a step of 0.10.1. It simplifies to 1.21−10.1=0.210.1=2.1\frac{1.21 - 1}{0.1} = \frac{0.21}{0.1} = 2.1, which is the slope of the secant line through (1,1)(1,1) and (1.1,1.21)(1.1,1.21).

The core idea here is the difference quotient — the ratio of the change in a function's output to the change in its input. For any function ff, the expression

f(a+h)−f(a)h\frac{f(a+h) - f(a)}{h}

gives the slope of the secant line between the points (a,f(a))(a, f(a)) and (a+h,f(a+h))(a+h, f(a+h)). In this problem, a=1a = 1 and h=0.1h = 0.1, so we're finding the average rate of change of f(x)=x2f(x)=x^2 over the interval from x=1x=1 to x=1.1x=1.1.

Why does this matter? Because this quotient is the foundation of the derivative — as hh shrinks to zero, the secant slope approaches the instantaneous slope (the derivative). Here, hh is fixed at 0.10.1, so we just compute directly.

Let's work through it step by step.

  1. Identify the pieces.

    We have f(x)=x2f(x) = x^2, so f(1)=12=1f(1) = 1^2 = 1 and f(1.1)=(1.1)2f(1.1) = (1.1)^2.

    Compute (1.1)2(1.1)^2: 1.1×1.1=1.211.1 \times 1.1 = 1.21.

    So f(1.1)=1.21f(1.1) = 1.21.

  2. Write the numerator.

    The numerator is f(1.1)−f(1)=1.21−1=0.21f(1.1) - f(1) = 1.21 - 1 = 0.21.

  3. Write the denominator.

    The denominator is 1.1−1=0.11.1 - 1 = 0.1.

  4. Form the quotient and simplify.

f(1.1)−f(1)1.1−1=0.210.1=21100÷110=21100×101=210100=2.1.\frac{f(1.1) - f(1)}{1.1 - 1} = \frac{0.21}{0.1} = \frac{21}{100} \div \frac{1}{10} = \frac{21}{100} \times \frac{10}{1} = \frac{210}{100} = 2.1.

Tip

Notice that 0.21/0.10.21/0.1 is just moving the decimal: 0.21÷0.1=2.10.21 \div 0.1 = 2.1. A quick check: 0.1×2.1=0.210.1 \times 2.1 = 0.21, so it's correct.

Watch out

A common mistake is to compute f(1.1)f(1.1) incorrectly — remember (1.1)2=1.21(1.1)^2 = 1.21, not 1.11.1 or 1.011.01. Also, don't forget the denominator is 0.10.1, not 11.

So the secant slope from x=1x=1 to x=1.1x=1.1 is 2.12.1. This makes sense: the derivative of x2x^2 at x=1x=1 is 22, and since h=0.1h=0.1 is small but not zero, the secant slope is slightly larger than 22 — exactly 2.12.1.

✓Final answer

The value is 2.1\boxed{2.1}.

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