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Exercise 9.1 · Q5

Q.Find the slope of a line, which passes through the origin, and the mid-point of the line segment joining the points P(0,−4)P(0, -4) and B(8,0)B(8, 0).

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The slope is found by first locating the midpoint of the segment joining PP and BB, then computing the slope of the line through that midpoint and the origin. The slope is −12\boxed{-\frac{1}{2}}.

The idea is straightforward: slope is the ratio of vertical change to horizontal change between two points. Here, one point is fixed at the origin (0,0)(0,0), and the other point is the midpoint of PP and BB. So the entire problem reduces to two simple steps — find the midpoint, then find the slope.


  1. Find the midpoint of P(0,−4)P(0,-4) and B(8,0)B(8,0). The midpoint formula is:

M=(x1+x22,y1+y22)M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)

Substituting P(0,−4)P(0,-4) and B(8,0)B(8,0):

M=(0+82,−4+02)=(4,−2)M = \left( \frac{0 + 8}{2}, \frac{-4 + 0}{2} \right) = (4, -2)

  1. Now find the slope of the line through the origin (0,0)(0,0) and M(4,−2)M(4,-2). Slope mm is given by:

m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}

Taking (x1,y1)=(0,0)(x_1, y_1) = (0,0) and (x2,y2)=(4,−2)(x_2, y_2) = (4,-2):

m=−2−04−0=−24=−12m = \frac{-2 - 0}{4 - 0} = \frac{-2}{4} = -\frac{1}{2} …

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