Q.A string of mass 2.50kg is under a tension of 200N. The length of the stretched string is 20.0m. If the transverse jerk is struck at one end of the string, how long does the disturbance take to reach the other end?
Wave Speed on a String – From Intuition to Formula
Imagine you and a friend hold a long, taut rope between you. If you give your end a quick flick upward, a bump travels along the rope toward your friend. That bump is a wave, and the speed at which it moves is the wave speed.
Now ask yourself: what determines how fast that bump travels? Two things stand out from everyday experience:
Tension – If you pull the rope tighter, the bump zips along faster. A loose rope makes the wave crawl.
Mass – If the rope is heavy (like a thick clothesline), the wave moves slower than on a light, thin string under the same tension.
So wave speed increases with tension and decreases with the "heaviness" of the string. That's the core intuition.
The Precise Statement
For a wave traveling along a stretched string, the wave speed v is given by:
v=μT
where:
T is the tension in the string (in newtons, N)
μ is the linear mass density – the mass per unit length of the string (in kg/m)
v=μT
This formula is exact for an ideal string (perfectly flexible, no stiffness, no damping). It comes from solving the wave equation for a string, but you can understand it physically.
Why the Square Root? A Quick Physical Argument
Think of a small segment of the string. The tension provides the restoring force that tries to straighten the string when it's bent. A higher tension means a stronger restoring force, so the wave accelerates faster – hence higher speed.
The mass per unit length μ is the inertia of the string. A heavier string resists acceleration more, so the wave slows down.
The square root appears because the relationship between force, mass, and acceleration isn't linear when you derive it properly. But the key takeaway is:
Important
Wave speed on a string depends only on the string's tension and its linear density – not on the frequency or amplitude of the wave.
This is a surprising and important result. Whether you send a slow, gentle ripple or a fast, sharp pulse, both travel at the same speed on the same string.
A Simple Example
A steel guitar string has μ=0.002kg/m and is under tension T=100N. What is the wave speed?
v=0.002100=50000≈224m/s
That's about half the speed of sound in air – fast enough that the wave reaches the other end almost instantly.
Common Mistakes to Avoid
Watch out
Do not confuse wave speed with the speed of the string's particles. The string itself moves up and down (transverse motion), but the wave travels horizontally. These are different speeds.
Wave speed does NOT depend on frequency. Changing how fast you flick your hand changes the frequency, but the wave still travels at v=T/μ.
Tension is not the same as force applied at the end. If the string is under tension T everywhere (ideal case), that's the value you use – not the force you apply to create the wave.
Where This Formula Comes From (A Glimpse)
If you're curious, the derivation uses Newton's second law on a tiny curved segment of the string. For small displacements, the net vertical force from tension equals μΔx times the acceleration. This leads to the wave equation:
∂t2∂2y=μT∂x2∂2y
Comparing with the standard wave equation ∂t2∂2y=v2∂x2∂2y gives v2=T/μ, hence v=T/μ.
Note
For exams, you only need to remember and apply the formula v=T/μ. The derivation is for understanding, not memorization – unless your syllabus explicitly asks for it.
Quick Summary
Quantity
Symbol
Effect on wave speed
Tension
T
Higher tension → faster wave
Linear density
μ
Heavier string → slower wave
Frequency
f
No effect
Amplitude
A
No effect
Final takeaway: Wave speed on a string is determined entirely by the string's material and how tightly it's stretched. It's a property of the medium, not the wave itself.
Many students find this page while searching "Wave Speed on String formula physics" or "Wave Speed on String important questions and answers"; the concept sits firmly within the Class 11 Physics NCERT/CBSE syllabus. It's also a frequent building block for numericals in JEE Main, NEET and state engineering/medical entrance exams, so treating it as a one-time memorisation task rather than an understood idea tends to backfire later.
Concept: Wave Speed on a String — the speed of a transverse wave depends only on tension and linear mass density, not on frequency or amplitude.
Step 1 — Linear mass density
μ=lengthmass=20.0m2.50kg=0.125kg/m
Step 2 — Wave speed
v=μT=0.125kg/m200N=1600=40.0m/s
Step 3 — Time to travel the length
t=vdistance=40.0m/s20.0m=0.500s
✓Final answer
The disturbance takes 0.500s to reach the other end.
The disturbance travels as a transverse wave on the string. Its speed depends only on tension and linear mass density, not on amplitude. The time taken is 0.5s.
The key idea here is that a transverse jerk (a pulse) propagates along a stretched string as a wave. The speed of such a wave is determined by two properties of the string: how tightly it is stretched (tension) and how heavy it is per unit length (linear mass density). Once we know the speed, the time to travel a given distance is simply distance divided by speed.
Let’s work through it step by step.
Find the linear mass density μ
The string has a total mass m=2.50kg and a total length L=20.0m.
Linear mass density is mass per unit length:
μ=Lm=20.02.50=0.125kg/m
Recall the wave speed formula for a string
For a transverse wave on a string under tension T, the wave speed v is given by:
v=μT
This formula comes from combining Newton’s second law with the restoring force due to tension. Intuitively: higher tension pulls the string back faster (higher speed), while heavier string resists motion more (lower speed).
v=μT
Plug in the values
Tension T=200N, μ=0.125kg/m:
v=0.125200=1600=40m/s
Calculate the time to travel the length
The pulse must travel the entire length L=20.0m at speed v=40m/s:
t=vL=4020.0=0.5s
Watch out
A common mistake is to forget that the mass given is the total mass of the string, not the mass per unit length. Always divide by the length first to get μ.
Tip
Notice that the time does not depend on how hard you jerk the string — the wave speed is fixed by tension and density. A bigger jerk just makes a bigger pulse, but it still travels at the same speed.
✓Final answer
The disturbance takes 0.5s to reach the other end.
Step 1: Linear mass density μ=Lm=20.02.50=0.125 kg/m.
Step 2: Wave speed on the string: v=T/μ=200/0.125=1600=40.0 m/s.
Step 3: Time to cross the full length: t=L/v=20.0/40.0=0.500 s.