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Exercise 7.1 · Q9

Q.Integrate the following function: ∫(2x2+ex)dx\int (2x^2 + e^x) dx

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The integral of a sum is the sum of the integrals. Using the Power Rule for x2x^2 and the exponential rule for exe^x, we get ∫(2x2+ex)dx=23x3+ex+C\int (2x^2 + e^x) dx = \frac{2}{3}x^3 + e^x + C.

Why This Works

Integration is the reverse of differentiation. When you see a sum like 2x2+ex2x^2 + e^x, you can break it apart because the derivative of a sum is the sum of derivatives — so the integral works the same way. Each term has its own standard rule.

The Power Rule for Integration says: to integrate xnx^n, increase the exponent by 1 and divide by the new exponent. That is,

∫xn dx=xn+1n+1+C(for n≠−1).\int x^n \, dx = \frac{x^{n+1}}{n+1} + C \quad \text{(for } n \neq -1\text{)}.

For exe^x, the rule is even simpler: the integral of exe^x is itself, ex+Ce^x + C, because the derivative of exe^x is exe^x.

The constant CC is crucial — it accounts for any constant that might have been lost when differentiating. Without it, your answer is incomplete.

Step-by-Step Solution

  1. Separate the integral Since integration distributes over addition:

∫(2x2+ex) dx=∫2x2 dx+∫ex dx.\int (2x^2 + e^x) \, dx = \int 2x^2 \, dx + \int e^x \, dx.

  1. Integrate the first term: 2x22x^2 Pull the constant 2 outside the integral:

2∫x2 dx.2 \int x^2 \, dx.

Apply the Power Rule with n=2n = 2:

∫x2 dx=x2+12+1=x33.\int x^2 \, dx = \frac{x^{2+1}}{2+1} = \frac{x^3}{3}.

So the first term becomes:

2⋅x33=23x3.2 \cdot \frac{x^3}{3} = \frac{2}{3}x^3.

  1. Integrate the second term: exe^x The integral of exe^x is simply exe^x: ∫ex dx=ex.\int e^x \, dx = e^x. …

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