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Exercise 9.1 · Q8

Q.Determine the order and degree, if defined, of the differential equation: y′+y=exy' + y = e^x

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This is a first-order, first-degree differential equation because the highest derivative present is y′y' (order 1) and it appears raised to the power 1 (degree 1). The equation is already in standard linear form.

Why Order and Degree Matter

When we classify a differential equation, we're asking two simple questions:

  1. Order: What is the highest derivative that appears in the equation?
  2. Degree: If we write the equation as a polynomial in the derivatives, what power is that highest derivative raised to?

These two numbers tell us a lot about the equation's behaviour and what methods we can use to solve it. For the equation y′+y=exy' + y = e^x, both answers are straightforward — but let's walk through the reasoning carefully.

Step-by-Step Solution

1. Identify the highest derivative

Look at each term in y′+y=exy' + y = e^x:

  • y′y' is the first derivative of yy with respect to xx.
  • yy is the function itself (zeroth derivative).
  • exe^x is a known function of xx, not a derivative.

The highest derivative present is y′y' — there is no y′′y'', y′′′y''', or higher. So the order is 1.

Tip

If you ever see a term like (y′′)3(y'')^3 or sin⁡(y′)\sin(y'), the order is still determined by the highest derivative, regardless of powers or functions applied to it. Here there's only y′y', so order = 1.

2. Check if degree is defined

Degree is defined only when the equation can be written as a polynomial in the derivatives — meaning no fractional powers, no trigonometric functions of derivatives, no absolute values, etc. Our equation is:

y′+y=exy' + y = e^x …

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